On 08/25/17 04:02, Kip Warner wrote:
I'd like to transform the following variable in my Makefile.am from...
files_only = a.foo b.foo c.foo d.foo ...
Into...
files_with_path = dir/a.foo dir/b.foo dir/c.foo dir/d.foo ...
Can you give more context why you need to substitute on the lef
On Sat, 2017-09-02 at 20:16 +1000, Peter Johansson wrote:
>
> On 9/2/2017 1:27 PM, Quinn Grier wrote:
> > You can fix this by generating the complete macro definitions
> > before
> > Automake runs and including them in Makefile.am.
>
> Another way to do this is to use
>
> macro `AX_AM_MACROS_STA
On 9/2/2017 1:27 PM, Quinn Grier wrote:
You can fix this by generating the complete macro definitions before
Automake runs and including them in Makefile.am.
Another way to do this is to use
macro `AX_AM_MACROS_STATIC' in Autoconf Macro Archive
https://www.gnu.org/software/autoconf-archive/a
On 2017-09-01 17:34, Kip Warner wrote:
> On Mon, 2017-08-28 at 11:03 -0700, Quinn Grier wrote:
>> A portable way to do this is to do the work in configure.ac and
>> transfer
>> it to the Makefile with AC_SUBST. For example, with an empty
>> Makefile.am
>> and the following configure.ac:
>>
>>
On Mon, 2017-08-28 at 11:03 -0700, Quinn Grier wrote:
> A portable way to do this is to do the work in configure.ac and
> transfer
> it to the Makefile with AC_SUBST. For example, with an empty
> Makefile.am
> and the following configure.ac:
>
> AC_INIT([Example], [1.0])
> AM_INIT_AUTO
On Mon, 2017-08-28 at 11:31 +0200, Mathieu Lirzin wrote:
> 'files_with_path' will not be interpreted by Automake, it will just
> copy the line in the generated Makefile. Since Make variables are
> macros the content of the variable will be simply be copied by Make
> where $(files_with_path) is used
On 2017-08-24 19:02, Kip Warner wrote:
> Hey list,
>
> I'd like to transform the following variable in my Makefile.am from...
>
> files_only = a.foo b.foo c.foo d.foo ...
>
> Into...
>
> files_with_path = dir/a.foo dir/b.foo dir/c.foo dir/d.foo ...
>
> I'm aware of GNU Make's $addprefi
Kip Warner writes:
> On Sun, 2017-08-27 at 19:44 +0200, Mathieu Lirzin wrote:
>> Would something like this work for you?
>>
>> files_with_path = `for f in $(files_only); do echo "dir/$$f"; done`
>
> Hey Mathieu,
>
> Thank you for the suggestion. I'm only hesitant to use that because I'm
> not
On Sun, 2017-08-27 at 19:44 +0200, Mathieu Lirzin wrote:
> Would something like this work for you?
>
> files_with_path = `for f in $(files_only); do echo "dir/$$f"; done`
Hey Mathieu,
Thank you for the suggestion. I'm only hesitant to use that because I'm
not sure if Automake needs to initiali
Hello,
Kip Warner writes:
> Hey list,
>
> I'd like to transform the following variable in my Makefile.am from...
>
> files_only = a.foo b.foo c.foo d.foo ...
>
> Into...
>
> files_with_path = dir/a.foo dir/b.foo dir/c.foo dir/d.foo ...
>
> I'm aware of GNU Make's $addprefix magic. I'm al
On Fri, 2017-08-25 at 11:33 -0400, Nick Bowler wrote:
> I'm not aware of any truly portable way to do this directly in make.
Hey Nick. Thanks for getting back to me.
Something that I guess I'm still confused about is why after more than
a decade does Automake not have a portable way to do these
Hello,
On 8/24/17, Kip Warner wrote:
> I'd like to transform the following variable in my Makefile.am from...
>
> files_only = a.foo b.foo c.foo d.foo ...
>
> Into...
>
> files_with_path = dir/a.foo dir/b.foo dir/c.foo dir/d.foo ...
I'm not aware of any truly portable way to do this dire
Hey list,
I'd like to transform the following variable in my Makefile.am from...
files_only = a.foo b.foo c.foo d.foo ...
Into...
files_with_path = dir/a.foo dir/b.foo dir/c.foo dir/d.foo ...
I'm aware of GNU Make's $addprefix magic. I'm also aware it's naughty
to use where portability
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