--- In Axapta-Knowledge-Village@yahoogroups.com, hitesh gupta
<[EMAIL PROTECTED]> wrote:
HI Hitesh,
I've check this function but I can't fully understand how to use it.
Anyway, I just write my function to compute for the difference in
months.
Thanks also to you NItesh for the codes, I've used
Hi,
I have found the answer in one of the post from arav.
Thanks for arav, this is exactly what I need.:)
Pls see below:
you can also try this function and see. it will also work.
(year(date2)*12+mthofyr(date2)) - (year(date1)*12+mtofyr(date1))
regards,
arav
--- In Axapta-Knowledge-Vil
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