Gabriel:
Thanks again for all the help. I'll download the OpenAxiom
version and try it.
William
On Tue, 10 Nov 2009 15:25:08 -0600
Gabriel Dos Reis wrote:
On Tue, Nov 10, 2009 at 1:37 PM, William Sit
wrote:
Hi Waldek:
Thanks. That is exactly what I want. Good solution. So
the
"trick"
Axiom now has an "API" (ApplicationProgramInterface) domain
(similar in spirit to Aldor's Builtin domain).
I will add devaluate to it.
I will also change the SExpression domain to export the symbol-*
functions from lisp with proper conversion functions.
Tim
William Sit wrote:
Tim:
Thanks, yo
On Tue, Nov 10, 2009 at 1:37 PM, William Sit wrote:
> Hi Waldek:
>
> Thanks. That is exactly what I want. Good solution. So the
> "trick" is to use ' instead of the string. So is the
> following a bug?
In OpenAxiom, you can get the name of a constructor as an Identifier:
(7) -> name constructor
On Tue, Nov 10, 2009 at 10:45 AM, William Sit wrote:
> Gabriel:
>
> Thanks for the response. Your script shows how to get the parameters, not
> the constructor. I do not have OpenAxiom installed (sorry). The question is
> whether I can test that the constructor is Fraction, or otherwise (like
> Fi
Tim:
Thanks, your method works. For me at least, it is much
easier to handle strings than SExpression.
Waldek also provided a working method using opOf (but that
involves SExpression, and the output in SExpression can be
misleading), which is perhaps a bug (see my reply to
Waldek).
To summarize
William,
a:='Fraction::SEX
is a lisp symbol. A lisp symbol is essentially the address of a data
structure
which is approximately
struct
symbol-function (pointer to code)
symbol-name (a string representation of the symbol)
symbol-package (the lisp package (a hash table poin
Hi Waldek:
Thanks. That is exactly what I want. Good solution. So the
"trick" is to use ' instead of the string. So is the
following a bug?
a:='Fraction::SEX
Fraction Type:SExpression
b:="Fraction"::SEX
Fraction Type:SExpression
(a=b)@Boolean
false Type Boolean
That is, I was deceive
William Sit wrote:
> Gabriel:
>
> Thanks for the response. Your script shows how to get the
> parameters, not the constructor. I do not have OpenAxiom
> installed (sorry). The question is whether I can test that
> the constructor is Fraction, or otherwise (like
> FiniteField) when the domain b
I'm not sure what you are asking. Are you having trouble with working in
the SExpression domain?
You can move the SExpressions out to other domains. Sometimes it is
painful but it works. So:
a:=FiniteField(5,2)
b:=devaluate(a)
string(SYMBOL_-NAME(b.1)$Lisp) ==> "FiniteField" (of type String)
in
It appears that to test the constructor, one must test a
candidate against a known one via the constructor itself,
and not be "fiat" by using a SExpression. Is this related
to hashing of pointers? Continuing with script in the
previous email (attached):
(11) -> EQ(c.1,d)$Lisp
(11) ()
Tim:
Sorry about the last message, please ignore.
The problem is solved (I was simply not being careful) and
made some false claims on the results.
(16) -> )clear all
All user variables and function definitions have been
cleared.
(1) -> a:=FiniteField(5,2)
(1) FiniteField(5,2)
Gabriel:
Thanks for the response. Your script shows how to get the
parameters, not the constructor. I do not have OpenAxiom
installed (sorry). The question is whether I can test that
the constructor is Fraction, or otherwise (like
FiniteField) when the domain belongs to the category
Field.
Thanks, Tim. That is exactly what I am looking for. Now I
would like to compare c.1 with some known constructor, say
Fraction. (In other words, given a domain of category
Field, I would like to know if it comes from the
constructor Fraction). I tried a few variations and each
time, Axiom says:
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