Re: [Axiom-developer] Testing if (72*a^3*b^5)^(1/2) is equivalent to 6*a*b^2*(2*a*b)^(1/2)

2010-03-08 Thread Martin Rubey
Ted Kosan writes: > I have been experimenting with Axiom to see how it compares to other > computer algebra systems. > > One of the things I tried testing was if Axiom could determine if > (72*a^3*b^5)^(1/2) was equivalent to 6*a*b^2*(2*a*b)^(1/2): > > (2) -> (72*a^3*b^5)^(1/2) - 6*a*b^2*(2*a*b)^

Re: [Axiom-developer] Testing if (72*a^3*b^5)^(1/2) is equivalent to 6*a*b^2*(2*a*b)^(1/2)

2010-03-08 Thread William Sit
Every "number" has two square roots. The expression may be zero and may not be zero, depending on which of the four possible interpretations you put on the square root. An expression like the one given can be interpreted at various levels in Axiom. Each "square root" can be interpreted as an

Re: [Axiom-developer] Testing if (72*a^3*b^5)^(1/2) is equivalent to 6*a*b^2*(2*a*b)^(1/2)

2010-03-07 Thread Tim Daly
Probably not. See: http://www.apmaths.uwo.ca/~djeffrey/Offprints/AMAI.pdf Tim Ted Kosan wrote: I have been experimenting with Axiom to see how it compares to other computer algebra systems. One of the things I tried testing was if Axiom could determine if (72*a^3*b^5)^(1/2) was equivalent to

[Axiom-developer] Testing if (72*a^3*b^5)^(1/2) is equivalent to 6*a*b^2*(2*a*b)^(1/2)

2010-03-07 Thread Ted Kosan
I have been experimenting with Axiom to see how it compares to other computer algebra systems. One of the things I tried testing was if Axiom could determine if (72*a^3*b^5)^(1/2) was equivalent to 6*a*b^2*(2*a*b)^(1/2): (2) -> (72*a^3*b^5)^(1/2) - 6*a*b^2*(2*a*b)^(1/2) +--+