Hi David,
I am trying to get active user in ldap.
Regards,
Jitendra
On Fri, Dec 5, 2014 at 4:12 PM, David Precious dav...@preshweb.co.uk
wrote:
On Fri, 5 Dec 2014 10:05:20 +0530
Jitendra Barik jbarik...@gmail.com wrote:
Could you please let me know please, why this code is not working as
On Fri, Dec 5, 2014 at 5:35 AM, Jitendra Barik jbarik...@gmail.com wrote:
Hi All,
Could you please let me know please, why this code is not working as I am
trying to validate my email id to my mail server?
my $ldap_server = google.com; # or some local mail server
my $ldap = Net::LDAP -
Brandon McCaig bamcc...@gmail.com writes:
Hope that helps.
Yes it does.
Thanks for the continuing review and criticism much needed in my case...
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Hello again!
Prompt me please elegant and 'vanilla' way to taint some scalar. My vars lost
their taint when I just split external string with regexp on param/val pairs,
without checking them for correctness.
And What do you say about this:
$foo.=substr($ENV{PATH},0,0); #$foo tainted if
On Sat, Dec 06, 2014 at 05:48:36PM +0300, Артём Варнайский wrote:
Hello again!
Prompt me please elegant and 'vanilla' way to taint some scalar. My vars lost
their taint when I just split external string with regexp on param/val pairs,
without checking them for correctness.
And What do you
ÐÑÑÑм ÐаÑнайÑкий wrote:
Hello again!
Prompt me please elegant and 'vanilla' way to taint some scalar. My vars
lost their taint when I just split external string with regexp on
param/val pairs, without checking them for correctness.
And What do you say about this:
Paul Johnson wrote:
I'm not sure whether there is a more elegant or more vanilla way to do
that. Appending the zero length substr is also the way it is done in
the perl core.
You would normally take the substr from the original string before
splitting it, unless you wanted to taint $foo even if
