I have an 11 digit number. I want to add another number to it and format to 11
digits as well.
my $amount1 = 14313562897;
my $amount2 = 0013625;
$amount = sprintf("%011d", $amount1 + $amount2);
print $amount."\n";
The answer perl gives me is -01
How can this be ?
As well, if th
Does anyone know how to format a string so that the spaces are padded on the
right, not the left.
Im using $dates = sprintf("%64s", $dates);
this right justifies the data and pads the left with spaces. I need the other
way around - left justified and padded with spaces on the right.
***
the latest file which ends in the
0d0a. Maybe my code is not correct or unstable ?
-Original Message-
From: Bob Showalter [mailto:[EMAIL PROTECTED]
Sent: Friday, 23 July 2004 22:17
To: David Clarke; [EMAIL PROTECTED]
Subject: RE: New Line / Chomp Query
David Clarke wrote:
> Hi, d
Hi, does anyone know what the new line character value is in Hex for a text file ? Is
it "0d 0a" ?
I'm trying to read in a line of text, chomp it, attach 3 digits at the end of this
line, then write this line to output file. But when I write it out, the original input
line is written out, the
Hi, I have a string of text that is thousands of characters in length. And I want to
break it up into smaller records of say 500 or 600 characters. Is there a Perl command
to help to do this or am I stuck with looping through the large input record and
counting field positions myself.
Thanks a
