Hi,
others have explained where the problem is ($foo is the scalar foo, not
the function foo), but...
>> Carter and Cathleen <[EMAIL PROTECTED]> writes:
> Now when I spit this through I get:
>
> + = x
Are you sure about this output? In particular about the "x" there.
Since you are doi
>> Sebastiao Alves Barata <[EMAIL PROTECTED]> writes:
> Why is $PREMATCH not changing on the seconde match?
Because there's no match the second time.
From perlvar(1):
$PREMATCH
$` The string preceding whatever was matched by the
last successful pattern matc
Hi,
>> Brent Buckalew <[EMAIL PROTECTED]> writes:
> other. What happens is that it reads in the numbers until there is a
> negative number. When it reaches a negative number, it places the
> remaining text in that variable.
I used your regular expression but I can't reproduce the proble
>> "M.W. Koskamp" <[EMAIL PROTECTED]> writes:
> \s* will match any number of spaces ([0-9.\-]*) will match the
> largest sequence of any character since there is a dot in the
> expression.
No. A '.' inside a character class is literal.
--
M.
>> Paul <[EMAIL PROTECTED]> writes:
> > if ( $formdata{view_name} ne "" ) {
> > $view = $formdata{view_name};
> > $viewtag = "1";
> > }
>
> For a simple boolean test, I usually find it more readable to be less
> explicit in these cases:
>
> if ( $formdata{view_name} ) {
> #
>> "if.then.else" <[EMAIL PROTECTED]> writes:
> > print "$windmill[$_ & 3]\r" and usleep(50) for 0..1;
>
> i'm a bit confussed with this print statement.
0..1 is a range from 0 to 1. (perlop(1), Range Operators)
for (foreach) is a modifier for the statement preceding it (per
[ Don't Cc: me, I read this mailing list, thank you ]
>> Troy May <[EMAIL PROTECTED]> writes:
> ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime;
> $thisday = (Sun,Mon,Tue,Wed,Thu,Fri,Sat)[(localtime) [6]];
> $s = (localtime)[0];
> $m = (localtime)[1];
> $m = ($m + 35) ;
