I see on the CGI web page that this:
===
use CGI;
$q = new CGI;
$query = $q-param( 'POSTDATA' );
===
will return the contents of this URI:
http://server/cgi.cgi?POSTDATA=posteddata
How do I code so that I don't have to use
On Thursday 31 Dec 2009 00:28:51 Bruce Ferrell wrote:
I see on the CGI web page that this:
===
use CGI;
$q = new CGI;
$query = $q-param( 'POSTDATA' );
===
will return the contents of this URI:
Shlomi Fish wrote:
On Thursday 31 Dec 2009 00:28:51 Bruce Ferrell wrote:
I see on the CGI web page that this:
===
use CGI;
$q = new CGI;
$query = $q-param( 'POSTDATA' );
===
will return the contents of this URI:
On Dec 30, 2009, at 23:28, Bruce Ferrell wrote:
I see on the CGI web page that this:
===
use CGI;
$q = new CGI;
$query = $q-param( 'POSTDATA' );
===
will return the contents of this URI:
On Thursday 31 Dec 2009 00:44:31 Bruce Ferrell wrote:
Shlomi Fish wrote:
On Thursday 31 Dec 2009 00:28:51 Bruce Ferrell wrote:
I see on the CGI web page that this:
===
use CGI;
$q = new CGI;
$query = $q-param( 'POSTDATA' );