On Oct 23, 12:15 pm, [EMAIL PROTECTED] (Jeevs) wrote:
On Oct 23, 2:19 pm, [EMAIL PROTECTED] wrote:
Hi
Thaks for ur valuable info..
my code is
my $total_nights=3;
$total_nights = 0.$total_nights if ((!($total_nights =~
/^0/)) ($total_nights 10));
my
Hi
Thaks for ur valuable info..
my code is
my $total_nights=3;
$total_nights = 0.$total_nights if ((!($total_nights =~
/^0/)) ($total_nights 10));
my $start_date=2008-03-24;
my ($year,$mon,$day) = split/-/,$start_date;
$day=($day+$total_nights);
Please don't open a new topic when you repeat the same question.
$day=($day+$total_nights);
I've said clearly,you can't do date oprations by this way.
See my before message that answered your question fully.
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On Oct 23, 2:19 pm, [EMAIL PROTECTED] wrote:
Hi
Thaks for ur valuable info..
my code is
my $total_nights=3;
$total_nights = 0.$total_nights if ((!($total_nights =~
/^0/)) ($total_nights 10));
my $start_date=2008-03-24;
my ($year,$mon,$day) = split/-/,$start_date;
HI
I need to get the $to as 18-10-2007
But it throws as 18.can u give the suggestion to get the
same format?
Thanks
#!/usr/perl/bin
$from=15-10-2007;
$to=$from+3;
print $from,\n;
print $to;
Regards,
Boniface
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On 10/22/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
HI
I need to get the $to as 18-10-2007
But it throws as 18.can u give the suggestion to get the
same format?
Thanks
#!/usr/perl/bin
$from=15-10-2007;
$to=$from+3;
print $from,\n;
print $to;
It looks like you want to do
Jeff Pang wrote:
On 10/22/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
HI
I need to get the $to as 18-10-2007
But it throws as 18.can u give the suggestion to get the
same format?
Thanks
#!/usr/perl/bin
$from=15-10-2007;
$to=$from+3;
print $from,\n;
print $to;
It looks like you
