Doh! I forgot about using $! All I need is
s/#$/\n/ ;
Thanks to Tor & Tanton for getting my brain in gear...
> -----Original Message-----
> From: Busse, Rich
> Sent: Tuesday, 23 July, 2002 09:00
> To: 'Perl Beginners'
> Subject: Replace last # with \n
>
> I have a string that looks like
>
> Operator Overview#PGM#Report about all configured
> operators#/opt/OV/bin/OpC/call_sqlplus.sh all_oper#
>
> I want to replace the last "#" with a newline. I've come up with a few
> ideas like
>
> substr ($_, rindex ($_, "#"), 1) = "\n" ;
> or
> substr ($_, length ($_) - 1, 1) = "\n" ;
> or
> chop ; $_ .= "\n" ;
>
> Are there any better ways, maybe using s/// or tr/// ? TIA...
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