On Sun, 10 Jun 2001, Charles Lu wrote:
> Variable "%hash" will not stay shared
I forgot to mention a few little details.. so here is your example
code with the corrections to get rid of the unsharing problem.
use strict;
my @list = ('apple',12, 'peach', 2, 'pear', 45);
&function_one(@list);
hya,
On Mon, 11 Jun 2001, Charles Lu wrote:
> > When I run the following code with the Warning flag I get the following
> > message:
> >
> > Variable "%hash" will not stay shared
> >
> > Here is my code:
> >
> > #trying to sort a Hash by Value
> > use strict;
my($var, @list, %hash);
sub fu
with use strict and use warnings putting the hash outside function_one as a
lexical or global both seem to work. Even making the hash inside function_one
a global seems to generate a warning if use warning is in effect. so putting a
function inside another seems to be no different from have it ou
On Sun, 10 Jun 2001, Charles Lu wrote:
> When I run the following code with the Warning flag I get the following
> message:
>
> Variable "%hash" will not stay shared
This can be a dangerous situation. Perl is complaining because
of the nested subroutine. The dangerous part is that it that t
On 10 Jun 2001, at 23:37, Charles Lu wrote:
>my @newhash = sort {$hash{$a} <=> $hash{$b}} keys %hash;
It's not quite an answer to your question, but I'm curious why you
nested the subroutine instead of just writing it like this?
--
Karen J. Cravens ([EMAIL PROTECTED])
When I run the following code with the Warning flag I get the following
message:
Variable "%hash" will not stay shared
Here is my code:
#trying to sort a Hash by Value
use strict;
my @list = ('apple',12, 'peach', 2, 'pear', 45);
&function_one(@list);
sub function_one {
my %hash = @_;
