Just put the part you want to extract in parentheses and then set $str equal
to $1...for example:
$str =~ /(\d\d\s*)$/;
$str = $1;
- Original Message -
From: Dhiraj P Nilange [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, January 29, 2002 4:12 PM
Subject: a very simple question
Tanton:
I am sure we could do it in one step as this:
$str =~ s/(\d\d\s*)$/$1;
Right?
-- Rex
-Original Message-
From: Tanton Gibbs [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, January 29, 2002 4:18 PM
To: Dhiraj P Nilange; [EMAIL PROTECTED]
Subject: Re: a very simple
Suppose I have a string in $str, I want to extract
some part of it based on regex and store it in the
same string. how do I do that?
say...
$str=~ $str /\d\d\s*$/;
($str) = $str =~ /(\d\d)\s*$; # Takes last two digits
# off end of string
Jonathan Paton
yep, that'll work too.
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Tuesday, January 29, 2002 4:18 PM
Subject: RE: a very simple question
Tanton:
I am sure we could do it in one step as this:
$str =~ s/(\d\d\s*)$/$1
I assume you want
$str = $1 if $str =~ /(\d\d\s*$)/;
always make sure to test for a match before using $1, $2, etc. If you
don't you may get a runtime warning.
On Tue, 2002-01-29 at 16:12, Dhiraj P Nilange wrote:
Hello
actually its very simple to answer for who knows basic perl.
Tanton:
I am sure we could do it in one step as this:
$str =~ s/(\d\d\s*)$/$1/;
Right?
Sorta, that'll take the end of the string according to the
match, and REPLACE IT with the end of the string - handy
huh.
So it matches:
'34 '
from:
'JunkJunkJunk34 '
and adds it to the
I assume you want
$str = $1 if $str =~ /(\d\d\s*$)/;
always make sure to test for a match before using $1, $2,
etc. If you don't you may get a runtime warning.
Only when you try to use $str later when it is undefined.
It should be checked, but perhaps not in the same place.
This
