Hi Frank,
On Wed, 25 Mar 2015 10:31:40 +0530
Frank Vino vinofra...@gmail.com wrote:
Hi Team,
How to understand Regular Expression in a easy way?
This page has links to some recommended tutorials about learning regular
expressions:
http://perl-begin.org/topics/regular-expressions/
Hi Frank,
when first learning regexps I read the section In the World of Regular
Expressions in the Lama-Book [1]. If you find this introduction to
slow, you might also take a look at chromatic's Modern Perl, which is
available for free [2].
Regards, Simon
Am
On Wed, 25 Mar 2015 10:31:40 +0530
Frank Vino vinofra...@gmail.com wrote:
Hi Team,
How to understand Regular Expression in a easy way?
Thanks,
Frank
Sorry Frank but there's no easy way. ☹
Some things to remember:
Some punctuation marks have special meaning, like periods, question
Thanks a lot Simon
-Frank
On Wed, Mar 25, 2015 at 5:44 PM, Simon Reinhardt si...@keinstein.org
wrote:
Hi Frank,
when first learning regexps I read the section In the World of Regular
Expressions in the Lama-Book [1]. If you find this introduction to
slow, you might also take a look at
Frank,
Just go through below site, it helps to build regex and test same easily.
http://www.regexr.com/
~Rahul
On Wed, Mar 25, 2015 at 10:42 AM, Akshay Mohit akshaymohit2...@gmail.com
wrote:
Just start using it and you will find it very easy to understand.
-Akshay
On Wed, Mar 25, 2015 at
Just start using it and you will find it very easy to understand.
-Akshay
On Wed, Mar 25, 2015 at 10:31 AM, Frank Vino vinofra...@gmail.com wrote:
Hi Team,
How to understand Regular Expression in a easy way?
Thanks,
Frank
When i run this script i get following Error
bash-4.2$ ./regex.pl
feature version v5.16.0 required--this is only version v1.160.0 at ./
regex.pl line 4.
BEGIN failed--compilation aborted at ./regex.pl line 4.
But I am using perl version as swon below.
bash-4.2$ perl -v
This is perl 5,
On 17 Sep 2014, at 17:08, Uday Vernekar vernekaru...@gmail.com wrote:
When i run this script i get following Error
bash-4.2$ ./regex.pl
feature version v5.16.0 required--this is only version v1.160.0 at ./regex.pl
line 4.
BEGIN failed--compilation aborted at ./regex.pl line 4.
But
when i change
use 5.16.0; to use feature ':5.10';
it works i get following output
bash-4.2$ ./regex.pl
Use of uninitialized value $3 in say at ./regex.pl line 7, DATA line 1.
Use of uninitialized value $4 in say at ./regex.pl line 7, DATA line 1.
Video1280x720
Use of uninitialized value $2 in
---Original Message---
From: Jing Yu logus...@googlemail.com
To: Viet-Duc Le leviet...@kaist.ac.kr
Sent date: 2014-09-17 12:20:29 GMT +0900 (Asia/Seoul)
Subject: Re: Regular expression: option match after a greedy/non-greedy match
Hi Viet-Duc Le,
On 17 Sep 2014
Hi Viet-Duc Le,
On 17 Sep 2014, at 10:23, Viet-Duc Le leviet...@kaist.ac.kr wrote:
Greeting from S. Korea !
I am parsing the output of ffmpeg with perl. Particular, I want to print only
these lines among the output and capturing the resolution, i.e. 1280x720.
Stream #0:0: Video:
Subject: Re: regular expression
On 05/07/2014 01:40 AM, John SJ Anderson wrote:
my @strings = (
^Modifications made by Danny Wong (danwong) on 2014/05/06 18:27:48
from database brms ,
^Modifications made by danwong on 2014/05/06 18:27:48 from database
brms²,
);
foreach my
On Tue, May 6, 2014 at 10:19 PM, Danny Wong (dannwong)
dannw...@cisco.com wrote:
What is a regular expression where I can extract ³danwong² from either
string (one string have () parentheses and the other doesn¹t have
parentheses)?
I'm not entirely sure what you're trying to accomplish, but
Both string are possible outputs, so I want to be able to grep for the
username only.
I tried this, but it works for the string without parentheses.
^Modifications made by danwong on 2014/05/06 18:27:48 from database brms,
$str1 =~ /by.*?[(]?(.*?)[)]?\s+on/i;
The one with partheses gives me
On Wed, May 7, 2014 at 1:19 AM, Danny Wong (dannwong)
dannw...@cisco.com wrote:
Hi Guys,
I have the following strings.
my $str1=^Modifications made by Danny Wong (danwong) on 2014/05/06
18:27:48 from database brms;
#$str1=^Modifications made by danwong on 2014/05/06 18:27:48 from
On Tue, May 6, 2014 at 10:30 PM, Danny Wong (dannwong)
dannw...@cisco.com wrote:
Both string are possible outputs, so I want to be able to grep for the
username only.
Well, if the username will always be either the only thing between
'by' and 'on', or in parens if it's not...
#! /usr/bin/env
On 05/07/2014 01:40 AM, John SJ Anderson wrote:
my @strings = (
^Modifications made by Danny Wong (danwong) on 2014/05/06 18:27:48
from database brms ,
^Modifications made by danwong on 2014/05/06 18:27:48 from database brms²,
);
foreach my $string ( @strings ) {
my( $match ) =
Not sure I get it, but would
/^fc3\/2\b/
(assuming you're looking for fc3/2 and not fc3/23) work?
hth
paolino
On 23 Aug 2013, at 17:06, jet speed speedj...@googlemail.com wrote:
Chaps,
Please i need help on the regular expression, i have the sample code below.
I only want to match the
On Fri, 23 Aug 2013 17:06:41 +0100
jet speed speedj...@googlemail.com wrote:
my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
my @check = qw( fc3/23 fc10/1 fc3/14 fc12/12 );
my $f2 = 'out.txt';
for my $element(@check) {
open my $fh2, '', $f2 or die could not open $f2: $!;
while (my $line =
On Fri, 23 Aug 2013 17:06:41 +0100
jet speed speedj...@googlemail.com wrote:
Chaps,
Please i need help on the regular expression, i have the sample code
below. I only want to match the entries from the array to the file
and print the matching line
for example if i only want to match
See sample code below
Chaps,
Please i need help on the regular expression, i have the sample code
below.
I only want to match the entries from the array to the file and print
the
matching line
for example if i only want to match fc3/23, in my code it prints both
the
lines fc3/2 and
On Aug 23, 2013, at 9:06 AM, jet speed wrote:
Chaps,
Please i need help on the regular expression, i have the sample code below.
I only want to match the entries from the array to the file and print the
matching line
for example if i only want to match fc3/23, in my code it prints both
Chaps,
I am testing all your code one by one, Appreciate your time and detailed
inputs.
Many Thanks
Sj
On Fri, Aug 23, 2013 at 6:01 PM, Jim Gibson jimsgib...@gmail.com wrote:
On Aug 23, 2013, at 9:06 AM, jet speed wrote:
Chaps,
Please i need help on the regular expression, i have
From: Dr.Ruud rvtol+use...@isolution.nl
On 2012-09-20 09:08, Octavian Rasnita wrote:
my ( $file_name ) = $data =~ /([^\\]+)$/g;
No need for that g-modifier.
--
Ruud
Yes, you are right. I added it by mistake.
Octavian
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For
From: Irfan Sayed irfan_sayed2...@yahoo.com
i have string 'c:\p4\car\abc\xyz.csproj'
i just need to match the xyz.csproj
i tried few option but does not help.
can someone please suggest
regards
irfan
my $data = 'c:\p4\car\abc\xyz.csproj';
my ( $file_name ) = $data =~ /([^\\]+)$/g;
got it myself :)
thanks a lot
$line_to_add =~ m/([a-zA-Z]+\.csproj)/;
regards
From: Irfan Sayed irfan_sayed2...@yahoo.com
To: Perl Beginners beginners@perl.org
Sent: Thursday, September 20, 2012 12:07 PM
Subject: regular expression help
i have string
On 09/20/2012 04:39 PM, Irfan Sayed wrote:
got it myself :)
thanks a lot
$line_to_add =~ m/([a-zA-Z]+\.csproj)/;
Hi Irfan,
Your solution will only match files that consist of ASCII alphabetic
characters followed by '.csproj'. It will also match these:
*
On Thu, 20 Sep 2012 17:13:07 +0930
Michael Brader mbra...@internode.com.au wrote:
A more idiomatic way to do this is to use the File::Spec module.
Inspect the output of this program for inspiration:
There's also File::Basename:
http://perldoc.perl.org/File/Basename.html
Regards,
thanks a lot for all the responses :)
regards
From: Shlomi Fish shlo...@shlomifish.org
To: Michael Brader mbra...@internode.com.au
Cc: beginners@perl.org
Sent: Thursday, September 20, 2012 2:53 PM
Subject: Re: regular expression help
On Thu, 20 Sep 2012
On 2012-09-20 09:08, Octavian Rasnita wrote:
my ( $file_name ) = $data =~ /([^\\]+)$/g;
No need for that g-modifier.
--
Ruud
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
On 15/07/2011 16:42, David Wagner wrote:
I have the following map:
map{[$_,(/^\d/ ? 1 : 0) . /^([^;]+)/,
/[^;]+;[^;]*;[^;]+;[^;]+;([^;]+);/]}
I had a failure during the night because some data field(s) had
a semi-colon in the data. So what I have is a
On 2011-07-15 17:42, Wagner, David --- Sr Programmer Analyst --- CFS wrote:
I have the following map:
map{[$_,(/^\d/ ? 1 : 0) . /^([^;]+)/,
/[^;]+;[^;]*;[^;]+;[^;]+;([^;]+);/]}
I had a failure during the night because some data field(s) had
a semi-colon
I ended up confused after reading your email.
Please specify INPUT + OUTPUT/condition.
You have already specify INPUT which is:
LOGICAL UNIT NUMBER 587
UID:60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID:
On 11-05-11 11:38 AM, jet speed wrote:
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find with regulare expression #if ($_=~
On 11/05/2011 16:38, jet speed wrote:
Hi All,
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find with regulare expression
On May 11, 8:38 am, speedj...@googlemail.com (jet speed) wrote:
Hi All,
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find
Hi All,
Thanks for your time and valuable inputs, Appreciate it.
I will try your suggestions and test it in my program.
Sj
Irfan Sayed wrote:
hi,
Hello,
i have following code.
$target = abc,xyz;
print $target\n;
$target =~ s/,/\s/g;
print $target\n;
i need to replace comma with whitespace for string abc,xyz
Whitespace is something that applies only to regular expressions but
the second part of the
John W. Krahn wrote:
Irfan Sayed wrote:
i have following code.
$target = abc,xyz;
print $target\n;
$target =~ s/,/\s/g;
print $target\n;
i need to replace comma with whitespace for string abc,xyz
Whitespace is something that applies only to regular expressions but
the second part of the
On 11-04-28 10:05 AM, Irfan Sayed wrote:
hi,
i have following code.
$target = abc,xyz;
print $target\n;
$target =~ s/,/\s/g;
print $target\n;
i need to replace comma with whitespace for string abc,xyz
the output shud be abc xyz
the above regular expression does not do that . please
: Thursday, April 28, 2011 7:47 PM
Subject: Re: regular expression
Irfan Sayed wrote:
hi,
Hello,
i have following code.
$target = abc,xyz;
print $target\n;
$target =~ s/,/\s/g;
print $target\n;
i need to replace comma with whitespace for string abc,xyz
Whitespace is something that applies only
thanks all
From: Shawn H Corey shawnhco...@ncf.ca
To: beginners@perl.org
Sent: Thursday, April 28, 2011 7:55 PM
Subject: Re: regular expression
On 11-04-28 10:05 AM, Irfan Sayed wrote:
hi,
i have following code.
$target = abc,xyz;
print $target\n
- Original Message -
From: Irfan Sayed irfan_sayed2...@yahoo.com
To: John W. Krahn jwkr...@shaw.ca; Perl Beginners beginners@perl.org
Sent: Thursday, April 28, 2011 9:28 AM
Subject: Re: regular expression
my logic was to just put the space character in place of comma and keep
rest
KK == Karl Kaufman krk...@comcast.net writes:
KK Well, to be precise, your conceptual logic was fine; the
KK implementation was flawed. As several have pointed out, you
KK weren't replacing the comma with a _space_ *character*, but with
KK the RegExp _whitespace_ *character class*.
to
2011/4/27 jet speed speedj...@googlemail.com
Hi,
Please could you advice, how can i write a regular expression for the
line below to capture 0079 and 69729260057253303030373
0079 Not Visible 69729260057253303030373
i tried this one, no luck
2011/4/27 jet speed speedj...@googlemail.com:
Hi,
Please could you advice, how can i write a regular expression for the
line below to capture 0079 and 69729260057253303030373
0079 Not Visible 69729260057253303030373
This might help?
$ perl -le '
$str=0079 Not
On 27/04/2011 11:47, jet speed wrote:
Please could you advice, how can i write a regular expression for the
line below to capture 0079 and 69729260057253303030373
0079 Not Visible 69729260057253303030373
i tried this one, no luck
/(^\d{4})\s\w+\s\w+\s+\d+/ig)
Hi all,
Thanks for all our inputs,
The regular expression below works fine if do it for single line, i am
trying to caputre the match $1, and $2 into array. only the first line
is pushed to the array. what am i doing wrong ?
how to get all the $1 and $2 match values for each line into arrary ?
On 4/27/11 Wed Apr 27, 2011 8:32 AM, jet speed
speedj...@googlemail.com scribbled:
Hi all,
Thanks for all our inputs,
The regular expression below works fine if do it for single line, i am
trying to caputre the match $1, and $2 into array. only the first line
is pushed to the array.
On Wed, Apr 27, 2011 at 04:32:57PM +0100, jet speed wrote:
Hi all,
Thanks for all our inputs,
The regular expression below works fine if do it for single line, i am
trying to caputre the match $1, and $2 into array. only the first line
is pushed to the array. what am i doing wrong ?
how
On 11-04-27 12:47 PM, Jim Gibson wrote:
The metasymbol \d matches the characters [0-9], not the extended hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
You can use the POSIX xdigit character class instead:
#!/usr/bin/env perl
use strict;
use
On Wed, Apr 27, 2011 at 2:48 PM, Shawn H Corey shawnhco...@ncf.ca wrote:
On 11-04-27 12:47 PM, Jim Gibson wrote:
The metasymbol \d matches the characters [0-9], not the extended
hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
You can use
On 2011-04-27 18:47, Jim Gibson wrote:
The metasymbol \d matches the characters [0-9],
Beware: the \d matches 250+ code points. So don't use \d if you only
mean [0-9].
not the extended hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
Or
Excellent Guys, I would like thank each one of you for inputs. Much
appreciated.
i got blinded by just the numbers 0079, i didn't cater for the next line
which is hex 007A, as one of you rightly pointed out [ 0-9A-Z] , does the
trick. its amazing to see different technique to achieve the same
At 13:39 +0300 12/04/2011, Shlomit Afgin wrote:
I need to write regular expression that will capitalize the first
letter of each word in the string.
Word should be word that her length is greater or equal to 3 letters
exclude the words 'and' and 'the'.
I tried:
$string = lc($string);
I agree completely with you, clean code is the best documentation.
But in your snippet I have to say: The use of $ anywhere in a program
imposes a considerable performance penalty on all regular expression
matches.
it would be better to avoid default/magic variables. I would consider
this
Shlomit Afgin wrote:
Hi
Hello,
I need to write regular expression that will capitalize the first letter of
each word in the string.
Word should be string with length that is greater or equal to 3 letters
exclude the words 'and' and 'the'.
I tried:
$string = lc($string);
$string =~
On 13 April 2011 11:40, Shlomit Afgin shlomit.af...@weizmann.ac.il wrote:
Hi
I need to write regular expression that will capitalize the first letter of
each word in the string.
Word should be string with length that is greater or equal to 3 letters
exclude the words 'and' and 'the'.
Hi Ramprasad,
thanks for your answer, but see below for my comments.
On Wednesday 13 Apr 2011 14:30:36 Ramprasad Prasad wrote:
On 13 April 2011 11:40, Shlomit Afgin shlomit.af...@weizmann.ac.il wrote:
Hi
I need to write regular expression that will capitalize the first letter
of
On Apr 12, 11:10 pm, shlomit.af...@weizmann.ac.il (Shlomit Afgin)
wrote:
Hi
I need to write regular expression that will capitalize the first letter of
each word in the string.
Word should be string with length that is greater or equal to 3 letters
exclude the words 'and' and 'the'.
On 13/04/2011 07:10, Shlomit Afgin wrote:
I need to write regular expression that will capitalize the first letter of
each word in the string.
Word should be string with length that is greater or equal to 3 letters
exclude the words 'and' and 'the'.
I tried:
$string = lc($string);
At 11:42 PM +0530 4/9/11, Sunita Rani Pradhan wrote:
Hi All
1. Can anybody guide me to write a regular expression to
verify correct Email address ?
peldoc -q valid How do I check a valid mail address?
2. I have written a regular expression to verify correct
Yes it is matching 167.249.0.0 .
-Sunita
-Original Message-
From: Jim Gibson [mailto:jimsgib...@gmail.com]
Sent: Saturday, April 09, 2011 11:50 PM
To: Perl Beginners
Subject: Re: regular expression for email id and IP address
At 11:42 PM +0530 4/9/11, Sunita Rani Pradhan wrote:
Hi All
use Regexp::Common qw/ net /;
$ip =~ /$RE{net}{IPv4}/;
On 2011-04-09 23:53 +0530, Sunita Rani Pradhan wrote:
Yes it is matching 167.249.0.0 .
But it's also matching things like 42. Feature?
Read about quantifiers, and also about the precedence of |.
--
- Olof Johansson
- www: http://www.stdlib.se/
- {mail,xmpp}: o...@ethup.se
- irc:
Hi Johan
You are right. Thanks for pointing out . Can you help me
getting it correct ?
Thanks
Sunita
-Original Message-
From: Olof Johansson [mailto:o...@ethup.se]
Sent: Sunday, April 10, 2011 12:13 AM
To: beginners@perl.org
Subject: Re: regular expression for email id and IP
On 2011-04-10 01:40 +0530, Sunita Rani Pradhan wrote:
Hi Johan
s/Johan/Olof/, but who keeps score?
You are right. Thanks for pointing out . Can you help me
getting it correct ?
Somebody already mentioned Regex::Common.
--
- Olof Johansson
- www: http://www.stdlib.se/
-
On 09/04/2011 21:30, Olof Johansson wrote:
On 2011-04-10 01:40 +0530, Sunita Rani Pradhan wrote:
You are right. Thanks for pointing out. Can you help me getting it
correct ?
Somebody already mentioned Regex::Common.
Use the same module for email addresses:
use Regexp::Common qw/ net
On 2011-03-06 17:22, Shlomit Afgin wrote:
I have a data that contain unseen characters that I want to delete.
The unseen characters can be ^L, ^N and other sign that I cannot copy but I
see them in my data.
Is someone know which regular can help me.
See perldoc perlre, specifically
I have a data that contain unseen characters that I want to delete.
The unseen characters can be ^L, ^N and other sign that I cannot copy but I
see them in my data.
Is someone know which regular can help me.
May you try the dos2unix command?
--
To unsubscribe, e-mail:
On 06/03/2011 16:22, Shlomit Afgin wrote:
I have a data that contain unseen characters that I want to delete.
The unseen characters can be ^L, ^N and other sign that I cannot
copy but I see them in my data.
Is someone know which regular can help me.
Hi Shlomit.
It would be better to list
2011/2/2 Shlomit Afgin shlomit.af...@weizmann.ac.il:
Hello,
I tried to convert html special characters to their real character.
For example, converting #8221; to .
I had the string
$str = #8220; test #8221; ניסיון ;
The string contain also Hebrew letters.
Could Encode
On 11-02-02 04:25 AM, Shlomit Afgin wrote:
I tried to convert html special characters to their real character.
For example, converting#8221; to.
I had the string
$str = #8220; test#8221; ניסיון ;
The string contain also Hebrew letters.
This seems to work:
#!/usr/bin/perl
use
At 18:52 +0800 03/02/2011, Jeff Pang wrote:
2011/2/2 Shlomit Afgin shlomit.af...@weizmann.ac.il:
I tried to convert html special characters to their real character.
For example, converting #8221; to .
I had the string
$str = #8220; test #8221; ÈÒÈÂÔ†¢ª
The string
On Tue, Nov 2, 2010 at 5:50 AM, Larsen, Henning Engelbrecht
h...@risoe.dtu.dk wrote:
I want to search a string for patterns but starting the search from the
_end_ instead of from the beginning, using a regular expression.
Try something like this:
$string = ...looong string possibly with
At 11:50 AM +0100 11/2/10, Larsen, Henning Engelbrecht wrote:
I want to search a string for patterns but starting the search from the
_end_ instead of from the beginning, using a regular expression.
Not a regular expression, but if all you are looking for is a
substring, use rindex:
perldoc
Hi Henning,
$catch = $1 if ($string =~ /.*(E)\d*\b/);
you can use this to test it:
$catch = $1 if ($string =~ /.*(E\d*)\b/);
--
Regards,
Akhthar Parvez K
http://www.sysadminguide.com/
UNIX is basically a simple operating system, but you have to be a genius to
understand the simplicity -
APK == Akhthar Parvez K akht...@sysadminguide.com writes:
APK Hi Henning,
APK $catch = $1 if ($string =~ /.*(E)\d*\b/);
APK you can use this to test it:
APK $catch = $1 if ($string =~ /.*(E\d*)\b/);
he didn't say there will be digits at the end. what if there aren't? his
example was
Hi Uri,
On Wednesday 03 Nov 2010, Uri Guttman wrote:
APK $catch = $1 if ($string =~ /.*(E)\d*\b/);
he didn't say there will be digits at the end. what if there aren't? his
example was just random text following the last E.
It will match even if there are no digits at the end:
input:
APK == Akhthar Parvez K akht...@sysadminguide.com writes:
APK Hi Uri,
APK On Wednesday 03 Nov 2010, Uri Guttman wrote:
APK $catch = $1 if ($string =~ /.*(E)\d*\b/);
he didn't say there will be digits at the end. what if there aren't? his
example was just random text following
On Wednesday 03 Nov 2010, Uri Guttman wrote:
try: 'E123EEExyz'
your \b at the end also breaks many cases.
perl -le 'print $1 if (EE123EExyz =~ /.*(E)\d*\b/)'
perl -le 'print $1 if (EE123abc =~ /.*(E)\d*\b/)'
perl -le 'print $1 if (EE123EExyzE =~ /.*(E)\d*\b/)'
E
the first two
On Nov 2, 3:50 am, h...@risoe.dtu.dk (Larsen, Henning Engelbrecht)
wrote:
I want to search a string for patterns but starting the search from the
_end_ instead of from the beginning, using a regular expression.
For instance I want to find the last 'E' in the string
...looong string possibly
On Aug 13, 1:47 pm, tobias.wage...@googlemail.com (irata) wrote:
I want to replace in a javscript structure like the one below every
occurence of {#...}, {?...}, {+...} and {=...} through
something different (also nested):
function() {
test1 = {#Caption};
test2 = {#Te{?st}};
On Aug 14, 6:28 am, dery...@gmail.com (C.DeRykus) wrote:
On Aug 13, 1:47 pm, tobias.wage...@googlemail.com (irata) wrote:
I want to replace in a javscript structure like the one below every
occurence of {#...}, {?...}, {+...} and {=...} through
something different (also nested):
On 8/13/10 Fri Aug 13, 2010 1:47 PM, irata
tobias.wage...@googlemail.com scribbled:
Hi...
I want to replace in a javscript structure like the one below every
occurence of {#...}, {?...}, {+...} and {=...} through
something different (also nested):
Check out the Text::Balanced module,
On Tue, Mar 2, 2010 at 5:45 PM, Durairaj Muthusamy tech.du...@gmail.comwrote:
Hi,
I am a newbie and need your help. The following script doesn't
display the first print statement like the second one.
Why?
@str = qw(NEW food foosball newstr foobasefoot);
$\ = \n;
foreach(@str)
{
Hello
Durairaj Muthusamy wrote:
I am a newbie and need your help. The following script doesn't
display the first print statement like the second one.
Why?
print First: $ if ?(foo.*)?;
print Second: $ if /(foo.*)/;
The delimiters for the regular expressions behave slightly
Thanks very much for clearing my doubts.
Regards,
Durai
On Tue, Mar 2, 2010 at 7:44 PM, Johann Markl
johann.ma...@googlemail.com wrote:
Hello
Durairaj Muthusamy wrote:
I am a newbie and need your help. The following script doesn't
display the first print statement like the second one.
DT == Dave Tang d.t...@imb.uq.edu.au writes:
DT a,b,c,d,e,f1,f2,g1,g2 which spoil my split(/,/).
DT Could someone provide some guidance?
use a CSV module. parsing csv files is a pain with regexes (even if
doable). there are very stable and fast csv modules on cpan so get one
and use it.
On Wed, Aug 26, 2009 at 02:23, Dave Tangd.t...@imb.uq.edu.au wrote:
Dear list,
I am trying to import entries in a csv file into a relational database,
however there are entries such as:
a,b,c,d,e,f1,f2,g1,g2 which spoil my split(/,/).
snip
Sounds like a job for [Text::CSV][1]. Of course,
On Wed, 26 Aug 2009 16:41:39 +1000, Chas. Owens chas.ow...@gmail.com
wrote:
On Wed, Aug 26, 2009 at 02:23, Dave Tangd.t...@imb.uq.edu.au wrote:
Dear list,
I am trying to import entries in a csv file into a relational database,
however there are entries such as:
a,b,c,d,e,f1,f2,g1,g2 which
On Wed, Aug 26, 2009 at 03:46, Dave Tangd.t...@imb.uq.edu.au wrote:
snip
for my $token ($line =~ /([,]|[^,]+)/g) {
I changed the single pipe (|) to double pipes (||) and $token also contained
empty strings. Could you explain the difference between the pipes?
snip
The pipe character in regexes
Hi Irfan
This code solve your problem
my $p=\ProductName\ = \8:EXFO RTU System 1.2.42\;
my ($val)=$p=~ m/\d+.\d+.(\d+)\/;
my $inval=$val+1;
$p=~s/$val/$inval/;
print===$p\n;
thanks
Ajay
-Original Message-
From: Irfan Sayed [mailto:irfan_sayed2...@yahoo.com]
Sent: Wednesday, June 17,
:41 PM
Subject: RE: regular expression help
Hi Irfan
This code solve your problem
my $p=\ProductName\ = \8:EXFO RTU System 1.2.42\;
my ($val)=$p=~ m/\d+.\d+.(\d+)\/;
my $inval=$val+1;
$p=~s/$val/$inval/;
print===$p\n;
thanks
Ajay
-Original Message-
From: Irfan Sayed [mailto:irfan_sayed2
Irfan Sayed wrote:
Hi All,
Hello,
need help on regular expression.
i have string like this
ProductName = 8:EXFO RTU System 1.2.42
now i want regular expression in such a way that it will change the line to :
ProductName = 8:EXFO RTU System 1.2.43
$ perl -le'
$_ = q[ProductName =
On Thu, 2009-01-08 at 20:25 -0800, howa wrote:
Hello,
Consider the string:
$s = '[[2003]] abc [[2008]] def';
I want to extract 2008 and def, so using
\[\[([\w\W^\]]+?)\]\]\s(.+?)
The regex match all string, even thought I have added to exclude: ^\]
inside the character
On Thu, Jan 8, 2009 at 23:25, howa howac...@gmail.com wrote:
Hello,
Consider the string:
$s = '[[2003]] abc [[2008]] def';
I want to extract 2008 and def, so using
\[\[([\w\W^\]]+?)\]\]\s(.+?)
The regex match all string, even thought I have added to exclude: ^\]
inside the character
Hello
On Nov 18, 8:18 pm, [EMAIL PROTECTED] (Rob Coops) wrote:
If you want to capture both lines you end up doing
somehting like this: (.*){0,1}$
Thanks.
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Rob Coops wrote:
On Tue, Nov 18, 2008 at 9:52 AM, howa [EMAIL PROTECTED] wrote:
Hello,
I have two strings:
1. abc
2. abc
The line of string might end with or not, so I use the expression:
(.*)[$]
Why it didn't work out?
This does not work because $ denotes the end of the
-Original Message-
From: howa [mailto:[EMAIL PROTECTED]
Sent: 18 November 2008 08:53
To: beginners@perl.org
Subject: Regular expression problem
Hello,
I have two strings:
1. abc
2. abc
The line of string might end with or not, so I use the expression:
(.*)[$]
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