From: Rob Dixon [rob.di...@gmx.com]
Sent: 09 November 2012 17:17
To: beginners@perl.org
Cc: Nemana, Satya
Subject: Re: variable definition error not caught when using strict and warnings
On 09/11/2012 17:08, Nemana, Satya wrote:
> Hi
>
> I am
On 09/11/2012 17:08, Nemana, Satya wrote:
Hi
I am a little confused with this program
Program:
use strict;
use warnings;
if ($999 == 1056)
{
print ("\nequal");
}
else
{
print ("\nnot equal");
}
What I expect: Perl to throw me an error as $999 variable is not defined, but
perl execu
On Fri, Nov 9, 2012 at 11:08 AM, Nemana, Satya wrote:
>
> if ($999 == 1056)
> {
> print ("\nequal");
> }
> else
> {
> print ("\nnot equal");
> }
>
> What I expect: Perl to throw me an error as $999 variable is not defined,
> but perl executes the code with a warning.(I don't expect the co
On Fri, Nov 9, 2012 at 11:08 AM, Nemana, Satya wrote:
> Program:
> use strict;
> use warnings;
>
> if ($999 == 1056)
> {
> print ("\nequal");
> }
> else
> {
> print ("\nnot equal");
> }
>
> What I expect: Perl to throw me an error as $999 variable is not defined,
> but perl executes the c
