Re: Using qr// with substitution and group-interpolation in thesubstitution part

On 10/25/23 10:32, Josef Wolf wrote: [...] Basically, I want to do the same as $data =~ s/^foo (whatever) bar$/bar $1 baz/mg; but with a different interface (because it has to be embedded into a bigger project), So I have come with this; sub substitute_lines { my ($contents,

Re: Using qr// with substitution and group-interpolation in the substitution part

ew Solomon" Cc: "Josef Wolf" ; Sent: Thursday, October 26, 2023 12:07 AM Subject: RE: Using qr// with substitution and group-interpolation in the substitution part Josef, Inspired by Levi's “eval” idea, here is my solution: sub substitute_lines { my ($content

RE: Using qr// with substitution and group-interpolation in the substitution part

things" command on your system. -Original Message- From: Claude Brown via beginners Sent: Thursday, October 26, 2023 8:07 AM To: Levi Elias Nystad-Johansen ; Andrew Solomon Cc: Josef Wolf ; beginners@perl.org Subject: RE: Using qr// with substitution and group-interpolation

RE: Using qr// with substitution and group-interpolation in the substitution part

Josef, Inspired by Levi's “eval” idea, here is my solution: sub substitute_lines { my ($contents, $regex, $subst) = @_; eval "\$contents =~ s/$regex/$subst/g"; return $contents; } $data = "foo whatever bar"; $data = &substitute_lines($data, qr/^foo (whatever) bar$/m, 'bar $1 baz'); p

Re: Using qr// with substitution and group-interpolation in the substitution part

That's a fun question, Josef! I don't think you can pass a replacement phrase around, so this is all I came up with: sub substitute_lines { my ($contents, $subst) = @_; $contents = $subst->($contents); return $contents; } my $data = "foo whatever bar"; print(substitute_lines($data, sub { $

Using qr// with substitution and group-interpolation in the substitution part

Hallo all, maybe this is not exactly a beginner question, but I could not find an appropriate mailing list (all other lists seem to be developer realted). Basically, I want to do the same as $data =~ s/^foo (whatever) bar$/bar $1 baz/mg; but with a different interface (because it has to be

Re: interpolation without double quotes

On Thu, 5 Jul 2018 09:58:52 -0500 p...@reason.net wrote: > Many thanks to Shlomi and Uri: as always, you’ve greatly boosted my > understanding of Perl! — Rick > You're welcome. -- - Shlomi Fish http://www.shlomifish.org/ ht

Re: interpolation without double quotes

forgot to double quote the variable. >> >> my $student_directory = '/data/students/' . $student_id; >> > > see http://perl-begin.org/tutorials/bad-elements/#vars_in_quotes . Perl often > stringifies expressions even outside interpolation, such as when being >

Re: interpolation without double quotes

Perl often stringifies expressions even outside interpolation, such as when being string-concatenated. > When I noticed this, I thought this was convenient: perl is trying to “do the > right thing.” But I worry that leaving them out may be bad coding practice; > if so, or you see other wort

Re: interpolation without double quotes

at leaving them out may be bad coding practice; if so, or you see other worthwhile improvements, please let me know. you don't need quotes on single scalar variables. in fact it is bad practice and can lead to bugs when you do that. what you did is not interpolation but ordinary concate

interpolation without double quotes

The following line works, even though I forgot to double quote the variable. my $student_directory = '/data/students/' . $student_id; When I noticed this, I thought this was convenient: perl is trying to “do the right thing.” But I worry that leaving them out may be bad coding practice; if so,

Re: Interpolation Problem

To second what Uri mentioned already, On Fri, Jul 15, 2016 at 11:42 PM, AC P wrote: > > > Argument "$command" isn't numeric in subtraction (-) at then it gives me > my directory. > > > This error message (I suspect it was a warning, can you check?) probably reported a line number. Could you p

Re: Interpolation Problem

keep getting interpolated before even reaching the TL1 device. i think you misunderstand what interpolation means. in perl a scalar in a string is interpolated to its value. I predictably receive: Argument "$command" isn't numeric in subtraction (-) at then it gives me my di

Interpolation Problem

Hello Perl gurus, I'm hoping someone here can provide a solution since I'm stuck. I'm trying to send TL1 commands resembling "RTRV-ALM-ALL;" (the simplest command you can send as an example here) via Net::SSH::Expect but they keep getting interpolated before even reaching the TL1 device. I predi

Re: interpolation problem in emacspipe.pl script from emacswiki

uffer (get-buffer-create "*piped*")))' }); system( qq{ emacsclient -n --eval '(with-current-buffer "*piped*" (insert "$_"))' }); notice how much easier they are to read and you can see the "" are for emacs lisp and not for perl. act

interpolation problem in emacspipe.pl script from emacswiki

acspipe.pl, i run it through "sed s/\"//g", whereby deleting the double quotes. There must be something about the interpolation. Maybe somebody has an idea? I am not an expert at this. Gabriel -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/

interpolation techniques (was Re: Here Docs)

>>>>> "t" == trapd00r writes: >> i would say to just use a temporary scalar variable. there is no shame >> in doing this and it is simpler than using the Interpolation module >> which is doing tied things and calling eval (which is dangerous).

Re: "Late" interpolation of a scalar variable inside a string

On Mar 14, 2009, at 5:24 PM, John W. Krahn wrote: Why not use sprintf() and '/foo/bar/%s/here' as the template: On Mar 14, 2009, at 5:19 PM, Chas. Owens wrote: * Search CPAN for template modules until you find one with the features you want, this one looks fairly close to what you want: htt

Re: "Late" interpolation of a scalar variable inside a string

Chap Harrison wrote: I want to compute a file pathname based on a "template" at runtime, when I know the value of a variable that the template uses. In other words, the template for the path name looks like this... /foo/bar/$project/here ...and I want to evaluate this expression once I have s

Re: "Late" interpolation of a scalar variable inside a string

On Sat, Mar 14, 2009 at 18:04, Chap Harrison wrote: > I want to compute a file pathname based on a "template" at runtime, when I > know the value of a variable that the template uses. > > In other words, the template for the path name looks like this... > > /foo/bar/$project/here snip > I've read

"Late" interpolation of a scalar variable inside a string

I want to compute a file pathname based on a "template" at runtime, when I know the value of a variable that the template uses. In other words, the template for the path name looks like this... /foo/bar/$project/here ...and I want to evaluate this expression once I have set the value of $pr

Re: Stopping variable interpolation/evaluation

> > Use print(), not printf(). > > -- > Gunnar Hjalmarsson > Email:http://www.gunnar.cc/cgi-bin/contact.pl- Hide quoted text - > > - Show quoted text - Thanx Gunnar and Octavian, print() and chomp() together did the job just fine. ~Pushkar -- To unsubscribe, e-mail: beginners-unsubscr...@perl.o

Re: Stopping variable interpolation/evaluation

pushkar.n...@gmail.com wrote: Hi, I have a line read in perl from a file that itself is a source code for languages like c/sv etc. The variable containing this line contains special characters like %d. When i print this line to another file, the %d is evaluated and a 0 is getting printed. How do

Re: Stopping variable interpolation/evaluation

From: Hi, I have a line read in perl from a file that itself is a source code for languages like c/sv etc. The variable containing this line contains special characters like %d. When i print this line to another file, the %d is evaluated and a 0 is getting printed. How do i overcome this and te

Stopping variable interpolation/evaluation

Hi, I have a line read in perl from a file that itself is a source code for languages like c/sv etc. The variable containing this line contains special characters like %d. When i print this line to another file, the %d is evaluated and a 0 is getting printed. How do i overcome this and tell perl t

Re: interpolation of function reference in a here doc

On Jul 2, 9:27 am, [EMAIL PROTECTED] (Rob Dixon) wrote: > Gabriel Striewe wrote: > > What do I do wrong? > > First of all, the ampersand subroutine designation is outdated and dangerous > and it is far better to use the indirect notation for a subroutine call: > > $hello->() > > Perl will interpola

Re: interpolation of function reference in a here doc

You may want to have a look at Interpolation.pm from CPAN. Jenda == [EMAIL PROTECTED] == http://Jenda.Krynicky.cz == : What do people think? What, do people think? :-) -- Larry Wall in <[EMAIL PROTECTED]> -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail

interpolation of function reference in a here doc

Dear List, I wanted to interpolate a function reference in a here doc. The following works fine: my $hello = sub { return "hello world!"; }; printf "hello $s\n", &$hello(); But when I use a heredoc instead, it doesn't work: print

Re: interpolation of function reference in a here doc

Gabriel Striewe wrote: I wanted to interpolate a function reference in a here doc. The following works fine: my $hello = sub { return "hello world!"; }; printf "hello $s\n", &$hello(); But when I use a heredoc instead, it doesn't work: print < First of all,

Re: interpolation of function reference in a here doc

rl printf is rarely used because double-quote strings allow interpolation of scalars and arrays, and because print accepts an arbitrary number of arguments. Interpolation does not understand function calls, though, so you either use a multi-argument call like this: print "hello "

Re: interpolation of function reference in a here doc

t when I use a heredoc instead, it doesn't work: print < You will encounter the problem if instead of printf "hello %s\n", &$hello(); you would have tried: print "hello &$hello()\n"; That's an issue with the rules of string interpolation. (Rea

Re: Interpolation of backslash-escapes

Randal L. Schwartz wrote: "Rob" == Rob Dixon <[EMAIL PROTECTED]> writes: Can anybody think of an elegant solution? Rob> eval "qq($val)"; s/elegant/hacky, dangerous, broken/ Consider $val = "), $yourcode_here, (". Old news, out of context, petulant. Rob -- To unsubscribe, e-mail: [EMAIL P

Re: Interpolation of backslash-escapes

> "Rob" == Rob Dixon <[EMAIL PROTECTED]> writes: >> Can anybody think of an elegant solution? Rob> eval "qq($val)"; s/elegant/hacky, dangerous, broken/ Consider $val = "), $yourcode_here, (". -- Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095 http://www.stonehe

Re: Interpolation of backslash-escapes

gt; Things I tried were for example >> $s= eval('' . "$val"); # (hoping to trigger the normal interpolation) or >> $s=~ s/\\(.)/"\\$1"/eg; >> but somehow i couldn't get it right ... >> >> Can anybody think of an elegant solution? > &

Re: Interpolation of backslash-escapes

Peter Daum wrote: > I am looking for an way to interpolate backslash-sequences > within a string with the usual perl semantics, e.g. > $s='1\t\2\t3\na\ b c' should become: > '123 > a b c' > > Things I tried were for example > $s= eval('' .

Re: Interpolation of backslash-escapes

Peter Daum wrote: > I am looking for an way to interpolate backslash-sequences within a string with the usual perl semantics, e.g. $s='1\t\2\t3\na\ b c' should become: '123 a b c' Things I tried were for example $s= eval('' . "$val"); # (hoping to

Re: Interpolation of backslash-escapes

On 11/3/06, Peter Daum <[EMAIL PROTECTED]> wrote: I am looking for an way to interpolate backslash-sequences within a string with the usual perl semantics That's what eval does, although you have to build your string with care. Don't let the user put their own data into that string; they can (

Re: Interpolation of backslash-escapes

result is different :-) > Things I tried were for example > $s= eval('' . "$val"); # (hoping to trigger the normal interpolation) or > $s=~ s/\\(.)/"\\$1"/eg; > but somehow i couldn't get it right ... > > Can anybody think of an elegant solution

Interpolation of backslash-escapes

I am looking for an way to interpolate backslash-sequences within a string with the usual perl semantics, e.g. $s='1\t\2\t3\na\ b c' should become: '123 a b c' Things I tried were for example $s= eval('' . "$val"); # (hoping to trigger the normal inter

interpolation problems (was: Re: help in regular expression)

Irfan J Sayed schreef: > #!/usr/local/bin/perl > > use warnings; > use strict; Good! > my $file = "c:\backup.pl"; Use my $file = 'c:\backup.pl'; or rather my $file = 'c:/backup.pl'; > open(FH,$file) || die " can't open a file"; Make that: open my $fh, '<', $file or die "Err

Re: What is Variable Interpolation [was: Re: Help Required on the Script]

John W. Krahn am Freitag, 7. April 2006 01.09: > D. Bolliger wrote: > > btw, @04 is not a valid (array) variable name; they must not start with a > > digit, as not keyword/builtin does. > > $ perl -Mwarnings -Mstrict -le' our @04 = 10 .. 14; print "@04"' > 10 11 12 13 14 > > You are probably thinki

Re: What is Variable Interpolation [was: Re: Help Required on the Script]

D. Bolliger wrote: > > btw, @04 is not a valid (array) variable name; they must not start with a > digit, as not keyword/builtin does. $ perl -Mwarnings -Mstrict -le' our @04 = 10 .. 14; print "@04"' 10 11 12 13 14 You are probably thinking scalars and/or lexicals. John -- use Perl; program

What is Variable Interpolation [was: Re: Help Required on the Script]

Mazhar am Donnerstag, 6. April 2006 11.48: > thanks Raymond for the help it works, > and what do u mean by variable interpolation Hello Mazhar It will help you a lot to know and use the documentation system of perl. You can get an overview by typing (on the command line): perldoc perl

Re: interpolation

print as: > >> > >>some perl $variable > >> > >>how can I force interpolation of '$variable'? > >> > >>one idea I thought of was: > >>#!/usr/bin/perl > >>my $var='variable'; > >>$string='some

Re: interpolation

John Doe wrote: The Ghost am Montag, 16. Januar 2006 06.34: I am storing text stings in a database. when I have the string: 'some perl $variable' which would print as: some perl $variable how can I force interpolation of '$variable'? one idea I thought of was: #!/

Re: interpolation

The Ghost am Montag, 16. Januar 2006 06.34: > I am storing text stings in a database. when I have the string: > > 'some perl $variable' > > which would print as: > > some perl $variable > > how can I force interpolation of '$variable'? > > o

Re: interpolation

I am storing text stings in a database. when I have the string: 'some perl $variable' which would print as: some perl $variable how can I force interpolation of '$variable'? one idea I thought of was: #!/usr/bin/perl my $var='variable'; $string='some

Re: interpolation

The Ghost am Freitag, 13. Januar 2006 21.23: > I know I could do that, but what if I don't know the variable names > in the string? > > > $sql=~s/\$Status/$Status/; > > could I do: > $sql=~s/\$(\S+)/${$1}/; > > On Jan 10, 2006, at 5:57 PM, John Doe wrote: > > The Ghost am Dienstag, 10. Januar 2006

Re: interpolation

I know I could do that, but what if I don't know the variable names in the string? $sql=~s/\$Status/$Status/; could I do: $sql=~s/\$(\S+)/${$1}/; On Jan 10, 2006, at 5:57 PM, John Doe wrote: The Ghost am Dienstag, 10. Januar 2006 21.57: I want to pull some text from a database: RxNumbe

Re: interpolation

The Ghost am Dienstag, 10. Januar 2006 21.57: > I want to pull some text from a database: > > RxNumber in (select RxNumber FROM restoreReports WHERE Status in > $Status) > > then I want perl to use this string and interpolate the variables > ($Status). > > so: > > my $Status= "('New','Old')"; > my

Re: string interpolation when reading from a file

n"; > print "K\t=>\t$k\n"; > > ### SQL_OUT is the filehandle that I am writing to > print SQL_OUT "$k\n"; $k _itself_ is interpolated into the double quoted string: $k contains a string with content looking like perl vars, $k is

Re: interpolation

Try changing your $Status variable to this: my $Status = '(' . '"' . join('","','New','Old') . '"' . ')'; that should give the results desired hope it helps. The Ghost wrote: I want to pull some text from a database: RxNumber in (select RxNumber FROM restoreReports WHERE Status in $Status)

interpolation

I want to pull some text from a database: RxNumber in (select RxNumber FROM restoreReports WHERE Status in $Status) then I want perl to use this string and interpolate the variables ($Status). so: my $Status= "('New','Old')"; my $sql=get_SQL_String(); #will get 'RxNumber in (select RxNum

string interpolation when reading from a file

Greetings -- I am reading text sql commands) from a file, chopping it into sections and then writing each section out to a different file. Within the text are perl variables that I had expected to be interpolated as they were written out to the new file but they are not. Here is a sample lin

Re: Interpolation Problem with Matching

RICHARDS, JIM wrote: I am trying to compare files names listed in a file to the actual files in a directory. My code is as follows: Your "code" won't compile. Please add the following two lines: use warnings; use strict; to the top of your program and let perl help you find the mistakes. The best

RE: Interpolation Problem with Matching

RICHARDS, JIM wrote: > I am trying to compare files names listed in a file to the actual > files in a directory. My code is as follows: > > > > Opendir(DIR,"name"); > > @files=readdir(DIR); > > > > Open(IN," > > > While() { > > If(/^pattern/) { > >

Interpolation Problem with Matching

I am trying to compare files names listed in a file to the actual files in a directory. My code is as follows: Opendir(DIR,"name"); @files=readdir(DIR); Open(IN,") { If(/^pattern/) { moveFile($_); } } Close(IN); Sub moveFile() {

Re: second-level string interpolation

At 10:39 AM 3/13/04 -0800, R. Joseph Newton wrote: >> my $header = <<'end_of_header'; >> # File: $filename >> end_of_header >> >> my $filename = 'xyz'; >> print $header, "\n"; # output: want to see # File: xyz, but get # File: >> $filename > >I am not sure how the above is any m

Re: second-level string interpolation

"Michael C. Davis" wrote: > Hi, Apologies if I'm bringing up a repeated topic. I searched the list > archive and the web and nothing specific has turned up so far. > > Is there a way to defer evaluation of the contents of a here-doc-defined > value such that one can embed variables in the here-d

Re: second-level string interpolation

Thanks everyone for the great ideas. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]

Re: second-level string interpolation

Randy W. Sims wrote: > I just realized that this might be a little misleading. If you break it > down to: > > my $result = eval $header; > print $result; > > You will get an uninitialized value error. What happens is that > > eval $header > > is first interpolated to > > eval { # File: xyz }

Re: second-level string interpolation

On 03/12/04 16:08, Randy W. Sims wrote: To elaborate a bit, the reason for the failure is that while the string is interpolated, it is then also evaluated as perl code, so in my $header = <<'end_of_header'; # File: $filename end_of_header my $filename = 'xyz'; print eval $header; the last stat

Re: second-level string interpolation

"Michael C. Davis" wrote: > > Hi, Apologies if I'm bringing up a repeated topic. I searched the list > archive and the web and nothing specific has turned up so far. > > Is there a way to defer evaluation of the contents of a here-doc-defined > value such that one can embed variables in the her

Re: second-level string interpolation

On 03/12/04 16:35, david wrote: Michael C. Davis wrote: Is there a way to defer evaluation of the contents of a here-doc-defined value such that one can embed variables in the here-doc and not have them evaluated until they are used later? Something like this: code: - use strict;

RE: second-level string interpolation

Michael C. Davis wrote: > Hi, Apologies if I'm bringing up a repeated topic. I searched the > list archive and the web and nothing specific has turned up so far. > > Is there a way to defer evaluation of the contents of a > here-doc-defined value such that one can embed variables in the > here-d

Re: second-level string interpolation

Michael C. Davis wrote: > > Is there a way to defer evaluation of the contents of a here-doc-defined > value such that one can embed variables in the here-doc and not have them > evaluated until they are used later? Something like this: > > code: > - > use strict; > use warn

second-level string interpolation

Hi, Apologies if I'm bringing up a repeated topic. I searched the list archive and the web and nothing specific has turned up so far. Is there a way to defer evaluation of the contents of a here-doc-defined value such that one can embed variables in the here-doc and not have them evaluated until

OT: referencing, derefrencing, and interpolation WAS: using a CONSTANT as a pathname

"Tassilo Von Parseval" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > On Sun, Jun 01, 2003 at 08:36:34PM -0400 Todd Wade wrote: > > > "Tassilo Von Parseval" <[EMAIL PROTECTED]> wrote in > > message news:[EMAIL PROTECTED] > > > On Sun, Jun 01, 2003 at 11:22:32AM +0200 Kevin Pfeiffer

RE: Best way to stop array interpolation.

Bakken, Luke wrote: > > > Here are two solutions I found: > > > > > > $rec->{"loans:a_$fld" . "[$i]"} = $tmp{$fld} || ''; > > > $rec->{"loans:a_$fld\[$i]"} = $tmp{$fld} || ''; > > > > > > Are there any other ways? Just curious. > > > > "loans:a_${fld}[$i]" also works. I like your second version

RE: Best way to stop array interpolation.

> > Here are two solutions I found: > > > > $rec->{"loans:a_$fld" . "[$i]"} = $tmp{$fld} || ''; > > $rec->{"loans:a_$fld\[$i]"} = $tmp{$fld} || ''; > > > > Are there any other ways? Just curious. > > "loans:a_${fld}[$i]" also works. I like your second version > above best. > > $ perl -MO=Depar

Best way to stop array interpolation.

Here's a quickie: I need to create a hash index out of a string that looks like this: loans:a_foo[0] If I build the index like this: $rec->{"loans:a_$fld[$i]"} = $tmp{$fld} || ''; perl thinks that $fld[$i] is an array element, which it isn't. Here are two solutions I found: $rec->{"loans:a_$

RE: Best way to stop array interpolation.

Bakken, Luke wrote: > Here's a quickie: > > I need to create a hash index out of a string that looks like this: > > loans:a_foo[0] > > If I build the index like this: > > $rec->{"loans:a_$fld[$i]"} = $tmp{$fld} || ''; > > perl thinks that $fld[$i] is an array element, which it isn't. > > Here

Re: Help with Hash values and variable interpolation

> 112.58.26.32.32770 > 192.35.51.30.53: 64596[|domain] (DF) > 112.58.26.32.32770 > 192.100.59.110.53: 24685 [1au][|domain] (DF) > 112.58.26.4.2506 > 216.148.227.69.80: . ack 3280436924 win 2920 (DF) > 112.58.26.4.2506 > 216.148.227.69.80: . ack 1759 win 1162 (DF) > 112.58.26.4.2498 > 66.207.130.

Re: Help with Hash values and variable interpolation

Joshua Scott wrote: > > Hello all, Hello, > I've got a file which contains ports and hostnames. I'd like to count the > number of instances that each item occurs in my file. I'm having a > difficult time with this. > > This is my script: Basically I'm splitting the first line a few times to

RE: Help with Hash values and variable interpolation

oshua [mailto:Joshua.Scott@;Jacobs.com] Sent: Monday, November 04, 2002 5:42 PM To: '[EMAIL PROTECTED]' Subject: Help with Hash values and variable interpolation Hello all, I've got a file which contains ports and hostnames. I'd like to count the number of instances that ea

Help with Hash values and variable interpolation

Hello all, I've got a file which contains ports and hostnames. I'd like to count the number of instances that each item occurs in my file. I'm having a difficult time with this. This is my script: Basically I'm splitting the first line a few times to get the data I need. What am I doing wro

RE: Interpolation problem

Thanks Japhy and Wags - I figured it was simple. Aloha => Beau. -Original Message- From: Jeff 'japhy' Pinyan [mailto:[EMAIL PROTECTED]] Sent: Wednesday, August 28, 2002 8:18 AM To: Beau E. Cox Cc: [EMAIL PROTECTED] Subject: Re: Interpolation problem On Aug 28, Beau E.

Re: Interpolation problem

On Aug 28, Beau E. Cox said: >I can't figure this one out. I have a requirement >to grab from some sort of input the elements of a regular >expression and execute it. All is fine except when I use >$1, $2, ... in the substitution, as: This is in the FAQ, and one of the MOST commonly asked FAQs I

RE: Interpolation problem

AIL PROTECTED]] Sent: Wednesday, August 28, 2002 11:07 To: [EMAIL PROTECTED] Subject: Interpolation problem Hi all - I can't figure this one out. I have a requirement to grab from some sort of input the elements of a regular expression and execute it. All is fine except when I use $1, $2, ... in the

Interpolation problem

Hi all - I can't figure this one out. I have a requirement to grab from some sort of input the elements of a regular expression and execute it. All is fine except when I use $1, $2, ... in the substitution, as: #!/usr/bin/perl use strict; use warnings; $_ = 'beau cox'; my $match = '(\w+)\s+(\w+

Re: Pattern-Matching var - interpolation.

hund 'k.a.t.z.e.' found at hund 'xyz' found at hund 'Connie' not found in Hund '123' found at hund Rgds, Connie ----- Original Message - From: "Sudarshan Raghavan" <[EMAIL PROTECTED]> To: "Perl beginners" <[EMAIL PROTECTED]> S

Re: Pattern-Matching var - interpolation.

On Fri, 19 Jul 2002, Sudarshan Raghavan wrote: > On Fri, 19 Jul 2002, Angerstein wrote: > > > Hello, > > I have a very unfunny problem, on which i am working for hours. > > > > I need to find out if a string contains an other specified string. > > I want to use pattern-matching. > > I can´t get

Re: Pattern-Matching var - interpolation.

On Fri, 19 Jul 2002, Angerstein wrote: > Hello, > I have a very unfunny problem, on which i am working for hours. > > I need to find out if a string contains an other specified string. > I want to use pattern-matching. > I can´t get a match together which make this. Look at my examples, > none o

Pattern-Matching var - interpolation.

Hello, I have a very unfunny problem, on which i am working for hours. I need to find out if a string contains an other specified string. I want to use pattern-matching. I can´t get a match together which make this. Look at my examples, none of the Matchings using vars works. If I replaces the va

Re: variable interpolation

gt;execute( CGI->param('NAME') ); > >Did you also print out the variable to prove that it does indeed contain >some data? Do you also have the RaiseError attribute turned on to die if >there are any SQL errors? > >Rob > > >-Original Message- >From:

RE: variable interpolation

> -Original Message- > From: bernabe diaz [mailto:[EMAIL PROTECTED]] > Sent: Friday, April 19, 2002 10:18 AM > To: [EMAIL PROTECTED] > Subject: variable interpolation > > > Hi everyone, > could somebody help me with the following problem: > i have a

RE: variable interpolation

t it does indeed contain some data? Do you also have the RaiseError attribute turned on to die if there are any SQL errors? Rob -Original Message- From: bernabe diaz [mailto:[EMAIL PROTECTED]] Subject: variable interpolation Thanks for help, but I tried that way too, and it does not wor

variable interpolation

hen I try to pass $variable_to a SQL statment the value of >> $variable_ was not passed >> so i can't fetch information fro the database. >> when i give the string to the SELECT statement directly every thing >> is fine, is working, that's why >>

Re: variable interpolation

ot; SELECT something FROM some_table WHERE some_key= '$variable_' "); > then when I try to pass $variable_to a SQL statment the value of > $variable_ was not passed > so i can't fetch information fro the database. > when i give the string to the SELECT statement

variable interpolation

ng is fine, is working, that's why I consider that it is a problem of interpolation of the variable . could anybody help me Thanks, BD -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]

Re: Variable Interpolation

From: [EMAIL PROTECTED] > Can you please help. > > When does Interpolation occur at Compile Time , Run Time or Both. So > far I know on both, then why does the following not work. ( how can I > get it to work ?) > > $scripts = 'cd $acu_home/bin \

Variable Interpolation

Hi . Can you please help. When does Interpolation occur at Compile Time , Run Time or Both. So far I know on both, then why does the following not work. ( how can I get it to work ?) $scripts = 'cd $acu_home/bin \n nohup ${srv}_ss $srv.ini > $acu_home/bin/$srv.out&'; $acu_

Re: Question: Interpolation in Strings

From: "G. E." <[EMAIL PROTECTED]> > As I' ve read in "Programming Perl", double-quoted strings are subject > to variable interpolation of scalars and list values. Nothing else > interpolates. So the following perl code won't comp

Re: Question: Interpolation in Strings

On Feb 2, G. E. said: >As I' ve read in "Programming Perl", double-quoted strings are subject to >variable interpolation of scalars and list values. Nothing else >interpolates. >So the following perl code won't compile: > > $st = "!--- &ge

Re: Question: Interpolation in Strings

"G. E." wrote: > > As I' ve read in "Programming Perl", double-quoted strings are subject to > variable interpolation of scalars and list values. Nothing else > interpolates. > So the following perl code won't compile: > > $st

Question: Interpolation in Strings

As I' ve read in "Programming Perl", double-quoted strings are subject to variable interpolation of scalars and list values. Nothing else interpolates. So the following perl code won't compile: $st = "!--- &get_header("Users")---!";

Re: Variable interpolation?

06/01/02 17:20:37, Jeff 'japhy' Pinyan <[EMAIL PROTECTED]> a écrit: >The contents of @string are raw text. You'll need to expand the variables >in it manually: > > perldoc -q 'expand variables' > >That FAQ will tell you what to do. Thanks, Jeff, for taking the time to answer. My problem was,

Re: Variable interpolation?

On Jan 6, Mad B.Jones said: >$name="Dave"; >$in="textfile.txt"; >open(INFILE, "<$in"); >@string=; >$string="$string[0]"; The contents of @string are raw text. You'll need to expand the variables in it manually: perldoc -q 'expand variables' That FAQ will tell you what to

Variable interpolation?

Hi everyone. A little thing I fail to understand... This of course works: $name="Dave"; $string="Hello $name"; print $string; outputting: Hello Dave Why, then, does it not work when I get the string "Hello $name" out of a file? $name="Dave"; $in="textfile.txt"; open(I

Re: Left side variable interpolation during associative array assignment?

er by year"; > my $arrayname = "\$sub$c"; > my $cursor = $dbh->prepare($SQL); > $cursor->execute; > while(@columns = $cursor->fetchrow){ > $arrayname{$columns[0]} = $columns[1]; #FAILED LEFT SIDE > INTERPOLATI

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