RE: Re[2]: param function

2002-03-17 Thread Gary Hawkins
> print CGI::header(); > print "hello\n"; > print "foo\n"; > print "bar\n"; > foreach my $line () { > my $result = &do_something($line); > } > use LWP::Simple; > my $credit_card_server = "secure.mybank.com"; > my $username = "my_secret_username"; > my $password = "my_pass

Re[2]: param function

2002-03-16 Thread Daniel Gardner
Saturday, March 16, 2002, 9:58:15 AM, Gary Hawkins wrote: > Web form element names automatically become script variable names and are > assigned their values... > use CGI 'param'; > for $name (param()) { > $$name = param($name); > } > The double $$ is not a typo. Your question resulti

Re[2]: param function

2002-03-16 Thread Daniel Gardner
Saturday, March 16, 2002, 12:42:40 AM, Tiller, Jason wrote: > my %params; > $params{$_} = param($_) foreach param(); > If I understand your code correctly, param() returns a list of all the > possible keys, right? If so, then the above code should work. You refer to > the parameters as $param{

RE: param function

2002-03-16 Thread Gary Hawkins
sz [mailto:[EMAIL PROTECTED]] > Sent: Friday, March 15, 2002 3:23 PM > To: perl > Subject: param function > > > hi, > I have a html form with over 100 fields, is there a quick way to > assign them in the way that the scalar name becomes the name of the > field and the valu

RE: param function

2002-03-15 Thread Tiller, Jason
rs as $param{name} instead of just $name. I hope that helps, :) ---Jason > -Original Message- > From: Mariusz [SMTP:[EMAIL PROTECTED]] > Sent: Friday, March 15, 2002 3:23 PM > To: perl > Subject: param function > > hi, > I have a html form with over 100 fi

Re: param function

2002-03-15 Thread Tanton Gibbs
form( e.g. @R::name ). Otherwise, you should use the scalar form (e.g. $R::name). If no namespace is given, the function will use 'Q'. Good luck! Tanton - Original Message - From: "Mariusz" <[EMAIL PROTECTED]> To: "perl" <[EMAIL PROTECTED]> Sent: Friday,

param function

2002-03-15 Thread Mariusz
hi, I have a html form with over 100 fields, is there a quick way to assign them in the way that the scalar name becomes the name of the field and the value of the field is being assigned to that scalar? I know I can just type it one by one: $name = param('name'); $lastname = param('lastname');