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Hi,
I have written a perl one liner that gets rid of
digits at the end of a word, but it
perl -ne 's/([a-z]\d+)/$1/g;' filename
It doesn't work, but if I use it in a script it works.
I want to know where am I going wrong. Also I want to
know how to not get rid of digits at the beginning of
a line but the ones that follow some chars
If input is like the one below,
This23
On Aug 19, Muthukumar said:
perl -ne 's/([a-z]\d+)/$1/g;' filename
If input is like the one below,
This23
is
a
45
good
thing
The result should be
This
is
a
45
good
thing
# perl -ne 'if ( ! /^\d+/ ) { s/[0-9]*$//;}print' test.log
That should be s/\d+$//, since \d is shorthand for [0-9]
anu p wrote:
Hi,
Hello,
I have written a perl one liner that gets rid of
digits at the end of a word, but it also gets rid of
digits if they are at the beginning of a line.
The one liner is
perl -ne 's/([a-z]\d+)/$1/g;' filename
It doesn't work, but if I use it in a script it works.
This should do what you want:
perl -pe's/(?=[[:alpha:]])\d+//g' filename
As per required ouput your one-line is showing to me as,
# perl -pe 's/(?=[[:alpha:]])\d+//g' test.log
This23
is
a
45
good
thing
# try this one.
# perl -pe 's/\d+//g if /^\D+/;' test.log
This
is
a
45
good
thing
anu p wrote:
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Subject:
perl one liiner
