Here's my problem:
$one = 'this (is a) 1/2 measure example';
Try and run that through a regex like
if ( $two =~ /$one/ ) {
and it's pretty ugly.
Who do I get the literal string for $one?
In this case I think it would be something like:
$two =~ /this \(is a\) 1\/2 measure example/
--
To unsu
On 3/7/06, Tom Allison <[EMAIL PROTECTED]> wrote:
> $one = 'this (is a) 1/2 measure example';
>
> Try and run that through a regex like
>
> if ( $two =~ /$one/ ) {
I think you're looking for the quotemeta() operator, and its cousin
the \Q escape. See perlfunc. Hope this helps!
--Tom Phoenix
Ston
;
if($two =~ /\Q$one/){
print "YES!\n";
}
##
-Original Message-
From: Tom Allison [mailto:[EMAIL PROTECTED]
Sent: Tuesday, March 07, 2006 10:59 AM
To: beginners@perl.org
Subject: regex grrr
Here's my problem:
$one = 'this (is a) 1
