Keep your replies on the list and you won't have to wait for me to wake
up again for an answer. ;)
On Nov 30, 2003, at 4:33 AM, B. Rothstein wrote:
thanks for the functions, but for some reason the sort does not seem
to be
coming out correctly, any idea why?
By default, sort() works
If I have a scalar variable that itslef is a list of names and numbers, for
example
$names = 'john 35, jack 18, albert 24, timmy 42'; is it possible, and if
so how can it be done to separate the individual names and ages from the
list in their scalar form in order to create new lists sorted by
B. Rothstein wrote:
If I have a scalar variable that itslef is a list of names and numbers, for
example
$names = 'john 35, jack 18, albert 24, timmy 42'; is it possible, and if
so how can it be done to separate the individual names and ages from the
list in their scalar form in order to
On Nov 30, 2003, at 12:33 PM, B. Rothstein wrote:
If I have a scalar variable that itslef is a list of names and
numbers, for
example
$names = 'john 35, jack 18, albert 24, timmy 42'; is it possible, and
if
so how can it be done to separate the individual names and ages from
the
list in their
If I have a scalar variable that itslef is a list of names, for example
$names = 'john, jack, albert, timmy; is it possible, and if so how can it
be done to separate the individual names from the list in their scalar form
in order to create a new list of sorted names. thanks for any suggestions.
On Nov 30, 2003, at 1:45 AM, B. Rothstein wrote:
If I have a scalar variable that itslef is a list of names, for example
$names = 'john, jack, albert, timmy; is it possible, and if so how
can it
be done to separate the individual names from the list in their scalar
form
in order to create a new
