Danny Wong:
Hello,
On Thu, Mar 19, 2015 at 09:25:02PM +, Danny Wong (dannwong) wrote:
Hi Perl GURU, I have a string like this:
'Baseline: (_bMgvUBQ_EeKsP6DECdq0Lg) 1 Initial Baseline
Initial Baseline of Component NGP-Diagnostics Sivakumar Subas
Oct 12, 2012 12:35:41 AM';
I’m trying
Hi Danny,
On Thu, 19 Mar 2015 21:42:53 +
Danny Wong (dannwong) dannw...@cisco.com wrote:
Nevermind. I used regex to accomplish what I wanted instead of the split
command. Thanks guys!
Just a note in general: sometimes when a simple split or a regex match fails
you may opt to employ
Hi Perl GURU,
I have a string like this:
'Baseline: (_bMgvUBQ_EeKsP6DECdq0Lg) 1 Initial Baseline Initial Baseline of
Component NGP-Diagnostics Sivakumar Subas Oct 12, 2012 12:35:41 AM';
I’m trying to perform a split via \s (spaces) delimiter, but this give me a
partial return of Initial
@perl.orgmailto:beginners@perl.org
Subject: split regex
Hi Perl GURU,
I have a string like this:
'Baseline: (_bMgvUBQ_EeKsP6DECdq0Lg) 1 Initial Baseline Initial Baseline of
Component NGP-Diagnostics Sivakumar Subas Oct 12, 2012 12:35:41 AM';
I’m trying to perform a split via \s (spaces) delimiter
Hi List,
I want to get that value of *-i* set in below line.
*Options=-ahello -mt -ml3 -idir1\dir2 -k -p -idir3\dir4 -m*
What is the best way to get the value of *-i* values into one array. For
ex: I want the output as: *dir1\dir2* and *dir3\dir4* into one array.
Thanks in advance.
Umesh T G am Donnerstag, 15. Dezember 2005 13.00:
Hi List,
Hi Umesh
I want to get that value of *-i* set in below line.
*Options=-ahello -mt -ml3 -idir1\dir2 -k -p -idir3\dir4 -m*
What is the best way to get the value of *-i* values into one array. For
ex: I want the output as:
Hi John,
I tried like this, where $line='*Options=-ahello -mt -ml3 -idir1\dir2
-k -p -idir3\dir4 -m'*
if (grep/^Options/,$line)
{
@inc=split(/-i/,$line);
foreach $word (@inc)
{
print $word\n;
}
I do not know how to proceed after this.
Thanks for your quick reply...
Thanks
Umesh
Umesh T G am Donnerstag, 15. Dezember 2005 14.20:
Hi John,
Hi Umesh
I tried like this, where $line='*Options=-ahello -mt -ml3 -idir1\dir2
-k -p -idir3\dir4 -m'*
if (grep/^Options/,$line)
{
@inc=split(/-i/,$line);
foreach $word (@inc)
{
print $word\n;
}
I do not know how to
Hi Joe,
just to correct my prevoius one, my $line does not have * in the begining,
that was a type. the $line value is like this
*Options=-ahello -mt -ml3 -idir1\dir2-k -p -idir3\dir4 -m*
my grep return the values correct to my array and the values in array will
be like this obviously:
Umesh T G wrote:
I tried like this, where $line='*Options=-ahello -mt -ml3 -idir1\dir2
-k -p -idir3\dir4 -m'*
This line won't compile. Which of the following is it?
$line='Options=-ahello -mt -ml3 -idir1\dir2 -k -p -idir3\dir4 -m';
$line='*Options=-ahello -mt -ml3 -idir1\dir2 -k -p
Umesh T G wrote:
Hi Joe,
just to correct my prevoius one, my $line does not have * in the begining,
that was a type. the $line value is like this
*Options=-ahello -mt -ml3 -idir1\dir2-k -p -idir3\dir4 -m*
my grep return the values correct to my array and the values in array will
be like
Umesh T G am Donnerstag, 15. Dezember 2005 15.31:
Hi Joe,
just to correct my prevoius one, my $line does not have * in the begining,
that was a type. the $line value is like this
*Options=-ahello -mt -ml3 -idir1\dir2-k -p -idir3\dir4 -m*
my grep return the values correct to my array
Thanks Very much John. :) it worked, but a small problem. if I have \
after the directory name, it does not take as new instanance.
for ex:
if my $line is*Options=-ahello -mt -ml3 -idir1\dir2-k -p
-idir3\dir4\ -m -n -i\dir5\dir6 -k*
**
then, I'm getting output like this,
dir1\dir2
Sorry for that John. It works fine.
Many thanks for your help.
Umesh
On 12/16/05, Umesh T G [EMAIL PROTECTED] wrote:
Thanks Very much John. :) it worked, but a small problem. if I have
\ after the directory name, it does not take as new instanance.
for ex:
if my $line is
14 matches
Mail list logo
