I find I'm undefining variables my assigning an
unitialized variable to defined value to make it
undefined (as exemplified below).
Is there a better way to do this?
my $k;
for($i = 0; $i $c; $i++){
if ( defined $k ){
print $x[$k];
my $t; # intentionally undefined
Wiggins d Anconia wrote:
my $k;
for($i = 0; $i $c; $i++){
if ( defined $k ){
print $x[$k];
my $t; # intentionally undefined
$k = $t; # undefine $k
} else {
$k = $i;
}
}
Unless this is a contrived example, just increment $i by 2 each loop.
If it is contrived then
I find I'm undefining variables my assigning an
unitialized variable to defined value to make it
undefined (as exemplified below).
Is there a better way to do this?
my $k;
for($i = 0; $i $c; $i++){
if ( defined $k ){
print $x[$k];
my $t; # intentionally undefined
$k = $t; #
On 4/1/2004 11:46 PM, Richard Heintze wrote:
I find I'm undefining variables my assigning an
unitialized variable to defined value to make it
undefined (as exemplified below).
Is there a better way to do this?
my $k;
for($i = 0; $i $c; $i++){
if ( defined $k ){
print $x[$k];
my
Richard Heintze wrote:
my $t; # intentionally undefined
$k = $t; # undefine $k
Just for clarity -
This isn't undefining it is
assignment of nothing to $k;
my $nothing;
print \n\$nothing\'s Value: $nothing and
\$nothing\'s length . length $nothing;
my $somthing = 100;
$somthing =
