Hi Leslie,
no, it seems like SVN 961 is working.
Best Regards,
Jürgen
On 06/15/2017 03:07 PM, Leslie S
Satenstein wrote:
is svn 961 recinded?
Sorry, please ignore that. I had not done an svn update.
With the latest svn I get:
¯1J11 | ¯12J10
0
... so it's looking good!
On 15 June 2017 at 13:50, Jay Foad wrote:
> I get:
>
> ¯1J11 | ¯12J10
> computing (-12,10) modulo (-1,11)
> ⎕CT is: 1e-13
> the quotient B ÷ A is: (0.
I get:
¯1J11 | ¯12J10
computing (-12,10) modulo (-1,11)
⎕CT is: 1e-13
the quotient B ÷ A is: (0.,0.)
the quotient rounded down is: (1,0)
¯11J¯1
On 15 June 2017 at 13:47, Juergen Sauermann
wrote:
> Hi,
>
> I have changed the implementation of *ComplexCell::b
Hi,
I have changed the implementation of ComplexCell::bif_residue()
to use a more
intuitive implementation of integral_within(). (the old
one used tolerant_floor() with
the dubious half-plane definition from the ISO standard).
The new ver
Hi Jay,
thanks again for the explanation. As a matter of fact, older GNU
APL versions did use a
more common-sense definition of tolerant floor, but then Fred
reported problems with the
Gaussian integers and I thought that this may be caused by me not
Another example from Fred:
¯1J11 | ¯12J10 ⍝ should be zero
¯11J¯1
This seems to be a consequence of the ISO standard's curious definition of
tolerant-floor. I would naively expect the tolerant floor of
A←0.99989J0.99989 to be 1J1, but according to the
standard (and h
