Hi Elias,
I think so. → without argument is ESCAPE not GOTO
0.
ESCAPE unrolls the )SI stack until it reaches immediate
execution.
Similar to throwing an exception and stopping at a try {}
block.
/// Jürgen
O
On 28 June 2017 at 18:22, Kacper Gutowski wrote:
> On Wed, Jun 28, 2017 at 06:02:03PM +0800, Elias Mårtenson wrote:
> > I have defined a function as such:
> >
> > ∇ Z ← foo X
> > →(X=0)/zero
> > Z ← 'not zero'
> > →
> > zero:
> > Z ← 'zero'
> > ∇
> >
> > When calling this function with a
On Wed, Jun 28, 2017 at 06:02:03PM +0800, Elias Mårtenson wrote:
> I have defined a function as such:
>
> ∇ Z ← foo X
> →(X=0)/zero
> Z ← 'not zero'
> →
> zero:
> Z ← 'zero'
> ∇
>
> When calling this function with a non-zero argument, I expect the return
> value to be 'not zero'. Instead
I have defined a function as such:
∇ Z ← foo X
→(X=0)/zero
Z ← 'not zero'
→
zero:
Z ← 'zero'
∇
When calling this function with a non-zero argument, I expect the return
value to be 'not zero'. Instead it simply exits the function. Is this
correct behaviour?
Regards,
Elias
