Hi,
extending Kacper's idea, you could also try:
(X/X)←∈(⍴¨X⊂X)⍴¨⊂1 0
It is a bit longer but may be faster because it avoids \.
/// Jürgen
On 03/20/2014 08:08 PM, Kacper Gutowski wrote:
On 2014-03-21 00:23:41, Elias Mårtenson wrote:
One of my experiments was very short, and tantalisi
Wow. That really works. Pretty neat!
(it does cause the interpreter to crash if you feed it unexpected
(non-boolean) data though, :-) )
Regards,
Elias
On 21 March 2014 03:08, Kacper Gutowski wrote:
> On 2014-03-21 00:23:41, Elias Mårtenson wrote:
> > One of my experiments was very short, and
On 2014-03-21 00:23:41, Elias Mårtenson wrote:
> One of my experiments was very short, and tantalisingly close to correct:
>
> ≠\V
>
> Unfortunately, it's not quite right. Does anyone have an idea how to coerce
> that one into being right?
I couldn't come up with anything better, but if you
One of my experiments was very short, and tantalisingly close to correct:
≠\V
Unfortunately, it's not quite right. Does anyone have an idea how to coerce
that one into being right?
Regards,
Elias
On 20 March 2014 16:10, wrote:
> Elias Mårtenson wrote:
> > Assume I have a binary sequence. S
Elias Mårtenson wrote:
> Assume I have a binary sequence. Say, something like this:
>
> 0 0 1 1 0 0 1 1 1 1 1 0 0 0 1 0 1 0 1 1 0 1 1 1
>
> Here, we can see a few sequences of consecutive ones. I want to zero out
> every second in each sequence. I.e, I'd like to get the following result:
>
> 0 0 1
I've been struggling with this one for days now, and I really need some
advice.
Assume I have a binary sequence. Say, something like this:
0 0 1 1 0 0 1 1 1 1 1 0 0 0 1 0 1 0 1 1 0 1 1 1
Here, we can see a few sequences of consecutive ones. I want to zero out
every second in each sequence. I.e,
