When the comment is inside of a substituted process.
#! /bin/bash -ex
#
tee >(
# this is nifty
echo hi there
)
The above works. Whereas the below fails.
#! /bin/bash -ex
#
tee >(
# ain't this nifty
echo hi there
)
It burps thusly:
./foo.sh: line 7: bad substit
Or maybe I'm not groking. When one compares against a b0rk symlink, the
result of -nt (newer than) is true--when it isn't!
mkdir directory
ln -s noexist symlink
touch -hr directory symlink
test directory -nt symlink &&echo yes ||echo no
They have identical mtimes (as set by touch)--i.e
On Sun, 7 Aug 2011, Chet Ramey wrote:
On 8/7/11 6:00 PM, Curtis Doty wrote:
local job jobcount=0
while read job
do ((jobcount++))
done < <(jobs)
As you suspect, the problem is with this part of the function. It doesn't
really have anything to do with PROMPT_COMMAND, t
I've recently refactored my PROMPT_COMMAND function to avoid superfluous
fork()s. In the body of the function, what was once this line:
local jobcount=$(jobs |wc -l)
is now this:
local job jobcount=0
while read job
do ((jobcount++))
done < <(jobs)
This works fine on bash 4. However,
On Tue, 21 Jun 2011, Chet Ramey wrote:
declare -A foo
read -a foo <<
Yes. It certainly shouldn't crash the shell. Try the attached patch and
let me know that it works for you. Thanks for the report.
Yep, thanks. Verified no segfault; only the error. Tested on 4.0, 4.1, and
4.2 in F
I did a stupid thing. Tried to read into an array--which is indexed--but
the variable is already an associative array.
declare -A foo
read -a foo <
11:30am Eric Blake said:
On 12/20/2010 11:25 AM, Curtis Doty wrote:
Not exactly sure if this is a bug. But I don't understand why only the
first time running ((i++)) returns an error exit status.
Because it follows the same semantics as 'expr', where status 1 is
reserved for a
Not exactly sure if this is a bug. But I don't understand why only the
first time running ((i++)) returns an error exit status.
Here's my script:
#! /bin/bash
echo $BASH_VERSION ${BASH_VERSINFO[5]}
set -x
#set -e
i=0
((i++))
echo $?
((i++))
echo $?
And here's what the output looks like:
4.1.7