On Fri, 06 Aug 2010 17:31:08 +, John Kelly wrote:
>>bash --version
>>GNU bash, version 4.1.7(1)-release (i586-pc-interix3.5)
>Backquote command substitution works, but $(...) does not.
>I built it like this:
>>CFLAGS="-O2 -march=i686" \
>>./c
>bash --version
>GNU bash, version 4.1.7(1)-release (i586-pc-interix3.5)
#! /usr/local/bin/bash
one=`cat data`
echo one=$one
two=$(cat data)
echo two=$two
>one=abc
>./xs: command substitution: line 7: syntax error near unexpected token `)'
>./xs: command substitution: line 7: `cat data)'
>two
On Mon, 04 Dec 2006 11:53:03 -0500, Chet Ramey <[EMAIL PROTECTED]>
wrote:
>> # With -e -o pipefail, this script should exit immediately upon returning
>> # from the pipeline, since grep does not match its string, and returns 1.
>This is not true, strictly speaking. The `-e' option applies to onl
#!/bin/bash
# With -e -o pipefail, this script should exit immediately upon returning
# from the pipeline, since grep does not match its string, and returns 1.
# However, any trivial compound statement at the end of the pipeline will
# cause the script to continue running. It's possible to work
