On Fri, 29 Feb 2008, Bob Proulx wrote:
Jan Engelhardt wrote:
I wanted to get the number of seconds since the start of the day.
echo $[`date +%s` % 86400];
unfortunately does not do the right thing ÿÿ it would show
82800 instead of 0 when it is (local) midnight.
I can't think of
Philip Rowlands [EMAIL PROTECTED] writes:
I might be misunderstanding the problem, but it seems easy enough to do
this calling date only once:
$ date +%T | awk -F: '{ print $1 * 3600 + $2 * 60 + $3 }'
67652
This will fail during the day after a DST transition.
Andreas.
--
Andreas Schwab,
Andreas Schwab wrote:
This will fail during the day after a DST transition.
Which points out a terrible bug in my suggestion of how to map the
range of 0-(N-1) to the range of 1-N!
Bob wrote this buggy code:
case $secondssincedaystart in (0) secondssincedaystart=86400 ;; esac
That will
Martin Bernreuther wrote:
on a common Linux system, everyone can use e.g.
ps and will see running processes of all users including
the command line arguments.
Yes. This is a long standing reason that programs that deal with
secure data such as passwords should avoid putting passwords in the
On Feb 29 2008 15:26, Bob Proulx wrote:
echo $[`date +%s` % 86400];
Note that the $[expression] syntax is deprecated and is scheduled for
removal from a future version of the shell. Please convert to using
the now standard $((expression)) syntax.
echo $(( $(date +%s) % 86400 ));
Jan Engelhardt wrote:
$(()) is easily confusable with $(), I therefore ask $[] to be not removed,
more like the reverse actually.
I am not able to influence the decision. I am just reporting how it
is documented.
Bob
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