--- jsdecastro28 <[EMAIL PROTECTED]> wrote:
> the problem is create a program that display the
> length of a string
> and other is concatenate two string
>
> this is my program...my only problem is the
> concatenation
>
> hope you will help me....ty
>
> #include <iostream.h>
> #include <conio.h>
>
> int length_str(char word[]);
> char cat_str(char word1[], char word2[]);
>
> void main()
> {
> clrscr();
> char word[50],word1[50],word2[50];
> int choice,z,y;
> do{clrscr();
> cout<<"\t\tSELECT YOUR CHOICES"
> <<"\n\t [1] - tells number of characters the
> string has"
> <<"\n\t [2] - Concatenation of string"
> <<"\n\t [3] - Exit"
> <<endl;
> cin>>choice;
>
> clrscr();
> switch(choice)
> {
> case 1: cout<<"Enter a word: ";
> cin>>word;
> z=length_str(word);
> cout<<"The no. of characters the string has
> is: "<<z;
> getch();
> break;
> case 2: cout<<"Enter 1st word: ";
> cin>>word1;
> cout<<"Enter 2nd word: ";
> cin>>word2;
> y=cat_str(word1,word2);
> cout<<"the concatenation word is: "<<y;
> getch
> break;
> case 3: cout<<"EXIT";
> getch
> break;
> }
> }while(choice == 1 || choice == 2);
> }
> int length_str(char word[])
> {
> int i=0;
> for(int j=0;word[j]!='\0';j++)
> i++;
> return i;
> }
> char cat_str(char word1[], char word2[])
> { char word3[100];
> int i=0,hold;
> hold=for(int j=0;word1[j]!='\0';j++)
>
> for(int j=0;word2[j]!='\0';j++)
> word1[hold++]=word2[i];
>
> return y;
>
>
> }
>
Please fix the program so it compiles. Numerous syntax
error exist.
What is the specific problem with the concatenation
function?
Mickey M.
Construction Partner Inc.
http://www.constructionpartner.com
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