Hello All,
I am using ajax helper to check, at the time of registration the
entered username is already exist in database or not.
For that I have used
?php
echo $form-text('User.login_name', array('class' = 'users', 'id' =
'login_name')); ?
$options = array('url' = 'update_select', 'update'
try this code for drowp down functionality
echo
$form-create('PopularFirm',array('url'=array('controller'='dashboards','action'='popular_firms'),'div'=false));
echo $form-input('name',
array('label'=false,'div'=false,'style'='margin-left:0;width:150px','type'='select','options'=$firmlist
Hello All,
I am using $ajax-observeField()
It is showing me error 'Form is not defined' in javascript console.
Does anyone has some solution for this?
Thanks in advance
Manisha.
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