Re: FindAll condition can not be an array?

2007-09-26 Thread Charlie van de Kerkhof
arams for a field have been > > > supported for quite some time in 1.2.x.x > > > > What DBO do you use ? MySQL? > > > > -Original Message- > > > From: cake-php@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf > > > > Of Charlie van de

Re: FindAll condition can not be an array?

2007-09-26 Thread Mike Green
arams for a field have been > > supported for quite some time in 1.2.x.x > > > What DBO do you use ? MySQL? > > > -Original Message- > > From: cake-php@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf > > > Of Charlie van de Kerkhof > > Sent: 26. september

RE: FindAll condition can not be an array?

2007-09-26 Thread Christian Winther
EMAIL PROTECTED] On Behalf Of Charlie van de Kerkhof Sent: 26. september 2007 13:09 To: Cake PHP Subject: Re: FindAll condition can not be an array? @Mike: Yes, that is my workaround now. But I get an array from another database and want to pass it to another db source for retrieval. @Christian

Re: FindAll condition can not be an array?

2007-09-26 Thread Charlie van de Kerkhof
> -Original Message- > From: cake-php@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf > > Of Charlie van de Kerkhof > Sent: 26. september 2007 12:36 > To: Cake PHP > Subject: FindAll condition can not be an array? > > Hi, > > (v1.2, latest SVN

RE: FindAll condition can not be an array?

2007-09-26 Thread Christian Winther
To: Cake PHP Subject: FindAll condition can not be an array? Hi, (v1.2, latest SVN version) I try to pass an array to the findAll function like this: $condition = array('id'=>array(2,5,6,9,12,45,78,43,76)); $this->Artist->findAll($condition); But the Query is written to the

Re: FindAll condition can not be an array?

2007-09-26 Thread Mike Green
I think you want to use find 'id' IN (2,5,6,4,6,7,8); $condition = array("id in (2,3,4,5,6,7,8)"); $this->Artist->findAll($condition); Mike On Sep 26, 11:35 am, Charlie van de Kerkhof <[EMAIL PROTECTED]> wrote: > Hi, > > (v1.2, latest SVN version) > > I try to pass an array to the findAll f

FindAll condition can not be an array?

2007-09-26 Thread Charlie van de Kerkhof
Hi, (v1.2, latest SVN version) I try to pass an array to the findAll function like this: $condition = array('id'=>array(2,5,6,9,12,45,78,43,76)); $this->Artist->findAll($condition); But the Query is written to the database is: SELECT * from Artist WHERE (2) AND (5) AND (6) AND (9) AND (12) AND