You need to put element sql_dump on your ajax layout too
Em terça-feira, 28 de fevereiro de 2012 11h30min07s UTC-3, heohni escreveu:
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> I have debug 2. but it will not return a sql statement, it's an ajax
> based request anyway
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> On 28 Feb., 14:02, Rodrigo Rodrigues Moyle
> wrote:
> > Set
I have debug 2. but it will not return a sql statement, it's an ajax
based request anyway
On 28 Feb., 14:02, Rodrigo Rodrigues Moyle
wrote:
> Set debug to 2
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> Em terça-feira, 28 de fevereiro de 2012 06h55min25s UTC-3, heohni escreveu:
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> > well, if I do it like the book says, I
Set debug to 2
Em terça-feira, 28 de fevereiro de 2012 06h55min25s UTC-3, heohni escreveu:
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> well, if I do it like the book says, I get no sql error any more, but
> the if ($this->Auth->login()) fails without any comment.
> In this case, how can I get the sql statement debugged which is
> run
well, if I do it like the book says, I get no sql error any more, but
the if ($this->Auth->login()) fails without any comment.
In this case, how can I get the sql statement debugged which is
running?
On 28 Feb., 10:33, luca capra wrote:
> Il 28/02/2012 09:55, heohni ha scritto:
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Even that way give me the same strange sql error
On 28 Feb., 10:33, luca capra wrote:
> Il 28/02/2012 09:55, heohni ha scritto:
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> > I did this, see above?
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> > On 28 Feb., 09:36, "@dariobarila" wrote:
> >> Hello,
> >> try to configure the Auth fields on the same level of $compon
Il 28/02/2012 09:55, heohni ha scritto:
I did this, see above?
On 28 Feb., 09:36, "@dariobarila" wrote:
Hello,
try to configure the Auth fields on the same level of $components =
array('Auth');
On 28 Feb, 09:33, heohni wrote:
...
$this->Auth->fields = array('username' => 'usr_use
I did this, see above?
On 28 Feb., 09:36, "@dariobarila" wrote:
> Hello,
> try to configure the Auth fields on the same level of $components =
> array('Auth');
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> On 28 Feb, 09:33, heohni wrote:
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> > Hi,
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> > as I only have to secure one controller, I put this into my
> > usersCo
Hello,
try to configure the Auth fields on the same level of $components =
array('Auth');
On 28 Feb, 09:33, heohni wrote:
> Hi,
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> as I only have to secure one controller, I put this into my
> usersController:
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> class UsersController extends AppController {
> var $name = 'User';
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Hi,
as I only have to secure one controller, I put this into my
usersController:
class UsersController extends AppController {
var $name = 'User';
var $components = array('Auth');
public function beforeFilter() {
parent::beforeFilter();
$this->Auth->fields = array('us
