Hi,
I want to use such a association:
var $hasMany = array(
'Comment' = array(
'className' = 'Comment',
'foreignKey' = 'user_id',
'conditions' = array('Comment.status' = '1'),
)
);
can I somehow use my current session value for the condition?
Like
'conditions' = array('UEB_FKID_SPR_ID' =
Add the ContainableBehavior to your AppModel class, and when using find:
$model-find('all', array(
'contain' = array(
'Comment' = array(
'conditions' = array(
'Comment.UEB_FKID_SPR_ID' = CakeSession::read('Config.languageID'
)
)
)
)))
--
Our newest site for the community: CakePHP Video
Hi,
I tried this, but with no effect, no error messae, but the select returns
all found data without the contain conditions.
Please help me
$results = ClassRegistry::init('Eigenschaftsarten')-find('all', array(
'contain' = array(
'Uebersetzungen' = array(
'fields' = 'UEB_TEXT,
On Fri, Mar 9, 2012 at 10:38 AM, heohni
heidi.anselstet...@consultingteam.de wrote:
var $hasMany = array(
'Uebersetzungen' = array(
'className' = 'Uebersetzungen',
'foreignKey' = 'UEB_NUMMER',
'conditions' = array('UEB_FKID_SPR_ID' = 1) = this is the place I
wanted to use my session
Hi!, did you just read what my answer was?
I tried, but the find statement simply ignores my condition with the
contain.
Do you know why or what I am doing wrong?
Am Freitag, 9. März 2012 14:30:49 UTC+1 schrieb heohni:
Hi,
I want to use such a association:
var $hasMany = array(
'Comment'
