Are these the conditions for a model related by a HasMany relationship? Most
probably CakePHP is using PHP's empty() function [http://php.net/empty] to
check the value of the foreignKey.
If that's the case, you may want to fill a ticket, but I doubt they would
fix it as it would change the current
I am submitting a value thru a form, based on the value a var is passed to
the query.
function getValueSub( $data) {
$primary = ( $data['primary'] == 4) ? array(0,1,2) : $data['primary'];
return array($this->alias . '.primary' => $primary);
}
But if zero is the value submitted its not p
$params = array(
'conditions' => array("Profile.company Like " => $i."%"),
'fields' => array('Profile.company','Profile.id'),
'contain' => false);
$this->find('first', $params);
Hope , it will work
On Sep 4, 3:49 am, "Dave Maharaj" wrote:
> I have this query in the model
>
> $pa
Dave,
'conditions' => array('Profile.company LIKE' => $i . '%'),
http://dev.mysql.com/doc/refman/5.0/en/string-comparison-functions.html
Andras Kende
http://www.kende.com/
On Sep 3, 2010, at 5:49 PM, Dave Maharaj wrote:
> I have this query in the model
>
> $params = array(
> 'conditions' =>
You should use % instead of *
On Sep 3, 4:49 pm, "Dave Maharaj" wrote:
> I have this query in the model
>
> $params = array(
>
> 'conditions' => array(
>
> 'Profile.company LIKE' => $i.'*'),
>
> 'fields' => array(
>
> 'Profile.company',
>
> 'Profile.id'),
>
> 'contain' => false);
>
> $this->fin
I have this query in the model
$params = array(
'conditions' => array(
'Profile.company LIKE' => $i.'*'),
'fields' => array(
'Profile.company',
'Profile.id'),
'contain' => false);
$this->find('first', $params);
Where $i is a single letter so I am trying to get the first record sta
@Miles J - Of course, I was concentrating on using cake to build the
SQL so much that I missed the obvious mistake in creating the
conditions array.
I don't suppose cake would handle the following:
array('Post.title LIKE'=>array('%mary%', '%tom%'), 'Post.description
LIKE'=>array('%mary%', '%tom%
@WebbedIT - Although that is correct, your example wont work. Simply
because you have conflicting indexes because they match, so 2 of them
would be overwritten. To fix this though you have to wrap them in an
array.
array(array('Post.title LIKE'=>'%mary%'), array('Post.description
LIKE'=>'%mary%')
I reckon you glossed over Miles J's point without full consideration.
Cake will do the OR work for you, consider ...
$this->Post->find('all', array(
'conditions' => array(
'Post.status' => 0,
'Post.rank <=' => 0,
'OR' => $convertedSearchString
)
));
All you need to do then is pas
Perfect. Works exactly as it should.
Thanks.
Dave
-Original Message-
From: Dr. Loboto [mailto:drlob...@gmail.com]
Sent: September-07-09 12:07 AM
To: CakePHP
Subject: Re: Query Help
Looks like you just forgot enclose your custom sql into brackets.
array(
'Post.status&
Cake 1.2 do not work with PHP 5.3. Downgrade PHP or take cake 1.3-dev
or wait for cake 1.3 stable.
On Sep 7, 1:12 pm, king wrote:
> Yestoday,i installed cakephp .
>
> Then,i visitedhttp://127.0.0.1。
>
> it displayed :
>
> Deprecated: Assigning the return value of new by reference is
> deprecate
Yestoday,i installed cakephp .
Then,i visited http://127.0.0.1。
it displayed :
Deprecated: Assigning the return value of new by reference is
deprecated in E:\Program Files\Apache Software Foundation
\Apache2.2\htdocs\cake-1.2\cake\libs\i18n.php on line 109 Deprecated:
Assigning the return valu
Looks like you just forgot enclose your custom sql into brackets.
array(
'Post.status' => 0,
'Post.rank <=' => $rank,
'('.$sql.')'
)
On Sep 7, 1:56 am, "Dave Maharaj :: WidePixels.com"
wrote:
> For some reason this query is pulling more results then that which is
> possible.
>
>
` LIKE '%tom%' OR `Post`.`description` LIKE
'%tom%'
And not LIKE '%marytom%'
It creates a string based on the values entered into the search.
-Original Message-
From: Miles J [mailto:mileswjohn...@gmail.com]
Sent: September-06-09 6:07 PM
To: CakePHP
Subject: R
Why dont you just use the built it or mechanics?
'OR' => array('Post.title LIKE' => '%'. $value .'%', 'Post.description
LIKE' => '%'. $value .'%')
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To p
escription` LIKE
'%mary%'
-Original Message-
From: Miles J [mailto:mileswjohn...@gmail.com]
Sent: September-06-09 4:42 PM
To: CakePHP
Subject: Re: Query Help
It seems like the OR is breaking it. What does the $sql variable look like?
--~--~-~--~~~---~--~
It seems like the OR is breaking it. What does the $sql variable look
like?
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For some reason this query is pulling more results then that which is
possible.
I am running a contain
$params = array('contain' => false,
'conditions' => array(
'Post.status' => 0,
'Post.rank <=' => $rank,
$sql
),
Try something like this:
$this->Article->bindModel(array('hasOne' => array(
'Category1' => array('className' => 'ArticleCategory'),
'Category2' => array('className' => 'ArticleCategory')
)));
$blah = $this->Article->findAll(array('Category1.name' => 'Blobble',
'Category2.name' => 'Blibble'));
Amit
I don't really think the declarations are wrong... but there can be
duplicate names in the Category model...
Here:
class Article extends AppModel {
var $name = 'Article';
var $hasMany = 'ArticleCategory';
}
class ArticleCategory extends AppModel {
var $name = 'ArticleCategory';
va
On 10/22/07, LS <[EMAIL PROTECTED]> wrote:
>
>
> Hello everyone!
> I promise I tried searching for this in this group and other sql-
> related groups... Maybe I just haven't searched for the right thing...
> Or even, maybe my head is not working properly...
>
> Here's the thing: I have 2 tables. On
Not really...
This is a one-to-many association...
The ArticleCategory field 'name' is what i want to search for.
I know I can do a one-to-many relationship... and then, I can grab all
the fields and show only those that match the criteria... What I was
wanting is for the sql server return me only
I assume that you also have a Category model?
Then setup the right associations in Article and Category and
ArticleCategory and use the $this->resursive = 1 var in Article or
Category to get the associations of that article or category
- Charlie
On Oct 22, 1:25 pm, LS <[EMAIL PROTECTED]> wrote:
Hello everyone!
I promise I tried searching for this in this group and other sql-
related groups... Maybe I just haven't searched for the right thing...
Or even, maybe my head is not working properly...
Here's the thing: I have 2 tables. One with articles and one with
categories... It goes like t
Thanks francky, that did the trick!
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try
conditions = array('AND' => array("Obj.length" => '>=6'), "Obj.length'
=> '<=13')))
On Oct 14, 4:29 am, MikeK <[EMAIL PROTECTED]> wrote:
> Can soeone please show me how to code this condition? 3 <= length <=
> 13
>
> conditions = array("Obj.length" => '>=6', "Obj.length' => '<=13');
>
> Only
Can soeone please show me how to code this condition? 3 <= length <=
13
conditions = array("Obj.length" => '>=6', "Obj.length' => '<=13');
Only the second condition is evaluated because
conditions['Obj.length'] = '<=13' is what gets set before the find.
The BETWEEN condition excludes the endpoi
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