Actually I still can't solve my problem.
Here is simply what I want :
- If a non logged in users goes to my site he sees homepage A
- If a logged in user goes to my site he sees homepage B
I have the code for the two homepages ready, but I can't do :
?php
if
Ok I reread some of the above comment, didn't knew what render was, so
I searched a little, and this works:
?php
if ($this-Session-check('Auth.User.id')) {
echo $this-element('home_logged');
} else {
echo $this-element('home');
}
?
Thanks !
On 3 jan, 19:33, J.
I want to display a complete other homepage when user is logged in,
but I don't want him to access the logged out user.
I thought I could use something like this :
?php
if ($this-Session-check('Auth.User.id')) {
echo(logged);
}
?
and replacing the echo by $this-redirect, but this doesn't work
you want to display some content only, if user is logged in right ?
you can do in a view something like that
if ($this-Session-check('Auth.User.id'))
{
//render element for example
}
--
Lep pozdrav, Tilen Majerle
http://majerle.eu
2012/1/2 J. contact.mysparet...@gmail.com
I want to display
In the controller you can use either:
if($this-Auth-user(User.id)){
$this-redirect(/homepage2);
// or
$this-render(homepage2);
}
Il 02/01/2012 14:42, Tilen Majerle ha scritto:
you want to display some content only, if user is logged in right ?
you can do in a view something like that
Thanks a lot !
On 2 jan, 15:32, luca capra luca.ca...@gmail.com wrote:
In the controller you can use either:
if($this-Auth-user(User.id)){
$this-redirect(/homepage2);
// or
$this-render(homepage2);
}
Il 02/01/2012 14:42, Tilen Majerle ha scritto:
you want to display
