@Ogalov: The correct way to check if a user is logged in within the
view is:
$session->check('Auth.User.id');
The point is you are not wanting to read a value as you are not then
using the value, you simply want to check if it exists and perform
some other logic. Jeremy gave you this answer and
Jeremy, sorry but the Session->check no found it in the 'if else', i
mean i use for read the user active that is all.
i dont now why you say "rash of peaple doing it wrong"??? or what
said webbedit !!! have i take it as sarcasm???..
I'm reading a lot of cake and I'm no expert .. but I'm getti
Lately there seems to be a rash of people doing it wrong, ignoring good advice
and then continuing to have problems (aka "Cake is buggy/rubbish").
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 8 Nov 2011, at 08:39, WebbedIT wrote:
>> Jeremy. thank for you answer.. (but I am going to
> Jeremy. thank for you answer.. (but I am going to ignore it)
You've got to laugh, Paul
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You're doing something wrong. If the user is not logged
$this->Session->read('Auth.User') will fail. $this->Session ->check is the
normal way to do it.
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 7 Nov 2011, at 15:32, Ogalav wrote:
> Jeremy. thank for you answer..
>
> i did it li
Jeremy. thank for you answer..
i did it like this and worked :
$session_active = $this->Session->read('Auth.User');
if (isset($session_active)){
echo 'Logout';
}
else {
Instead of checking the session, do this:
Session->check('Auth.User')) {
echo 'Logout';
} else {
echo 'Login';
}?>
Jeremy Burns
Class Outfit
Tel: +44 (0) 208 123 3822
Mob: +44 (0) 7973 481949
Skype: jeremy_burns
http://www.classoutfit.c
Hi,
i want show in the default.ctp in the header one content that will
have link for logut or login, depending on the recording session
active.
so, i´m doing this:
views/layouts/default.ctp
Session->read('Auth.User'))){
e
