William L. Maltby wrote:
> On Mon, 2009-08-17 at 19:55 +0100, James Bensley wrote:
>> I can't think of the exact syntax at the minute but something like;
>>
>> if $# => 4 then
>> for i = 1 to ($# - 4)
>> echo "arg number $i is $expr($i)"
>> next
>> fi
>
> $ echo $*
> 1 2 3 4
> $ \
On Mon, 2009-08-17 at 19:55 +0100, James Bensley wrote:
> I can't think of the exact syntax at the minute but something like;
>
> if $# => 4 then
> for i = 1 to ($# - 4)
> echo "arg number $i is $expr($i)"
> next
> fi
$ echo $*
1 2 3 4
$ \
> while [ "$1" != '' ] ; do
> echo $1
>
I can't think of the exact syntax at the minute but something like;
if $# => 4 then
for i = 1 to ($# - 4)
echo "arg number $i is $expr($i)"
next
fi
$# is the number of args passed so just pass the total number of args
minus four ($~-4)
That syntax is all wrong, but somebody on t
>maybe you call shift (more than once) and then pass $...@?
Didn't know bash had a shift!
Thx!
jlc
___
CentOS mailing list
CentOS@centos.org
http://lists.centos.org/mailman/listinfo/centos
On Mon, Aug 17, 2009 at 10:01 AM, Joseph L.
Casale wrote:
> I am trying to write a script that can pass cmd line args into an
> executable it runs, I need at least 4 args, but I need to pass the rest
> to it in the script if they exist.
>
> $@ doesn't help because I use the 1st and 2nd etc, so how
I am trying to write a script that can pass cmd line args into an
executable it runs, I need at least 4 args, but I need to pass the rest
to it in the script if they exist.
$@ doesn't help because I use the 1st and 2nd etc, so how do I elegantly
handle passing args 4+ if they exist on the end of t
6 matches
Mail list logo
