On 03/31/2011 05:25 AM, Jerry Geis wrote:
> I can do "simply" search and replace with sed.
> However, I want to setup httpd.conf from a script
> that changes the default "/" which is presently:
>
>
> Options FollowSymLinks
> AllowOverride None
>
>
> and change it to the following:
>
On Thu, Mar 31, 2011, Jerry Geis wrote:
>I can do "simply" search and replace with sed.
>However, I want to setup httpd.conf from a script
>that changes the default "/" which is presently:
While this can be done with sed, it's generally a lot easier to do with
python or perl, particularly when dea
I can do "simply" search and replace with sed.
However, I want to setup httpd.conf from a script
that changes the default "/" which is presently:
Options FollowSymLinks
AllowOverride None
and change it to the following:
Order Deny,Allow
Deny from all
AllowOverride None
H
> -Original Message-
> From: centos-boun...@centos.org
> [mailto:centos-boun...@centos.org] On Behalf Of John Doe
> Sent: Friday, June 11, 2010 10:50 AM
> To: CentOS mailing list
> Subject: Re: [CentOS] script question
>
> From: "m.r...@5-cent.us"
From: "m.r...@5-cent.us"
>> On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis <
>> if I do: echo jj_$VERSION_jj
>> I get jj_
>> How do I get the $VERSION to work with the
>> underscores like the dashes
> echo \_$VERSION\_
Or:echo jj_${VERSION}_jj
JD
_
> On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis
> wrote:
>> in a script if I have:
>> VERSION="3.2.0"
>>
>> I can do:
>> echo jj-$VERSION-jj
>> and get jj-3.2.0-jj
>>
>> however if I do:
>> echo jj_$VERSION_jj
>> I get jj_
>>
>> How do I get the $VERSION to work with the underscores like the dashes
On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis wrote:
> Hi all,
>
>
> in a script if I have:
> VERSION="3.2.0"
>
> I can do:
> echo jj-$VERSION-jj
> and get jj-3.2.0-jj
>
> however if I do:
> echo jj_$VERSION_jj
> I get jj_
>
> How do I get the $VERSION to work with the underscores like the dashes d
>
> How do I get the $VERSION to work with the underscores like
> the dashes do.
echo JJ\_$VERSION\_JJ
***
This email and any files transmitted with it are confidential and
intended solely for the use of the individual or entity t
> however if I do:
> echo jj_$VERSION_jj
> I get jj_
>
> How do I get the $VERSION to work with the underscores like the dashes
> do.
echo jj_${VERSION}_jj
___
CentOS mailing list
CentOS@centos.org
http://lists.centos.org/mailman/listinfo/centos
On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis wrote:
> Hi all,
>
>
> in a script if I have:
> VERSION="3.2.0"
>
> I can do:
> echo jj-$VERSION-jj
> and get jj-3.2.0-jj
>
> however if I do:
> echo jj_$VERSION_jj
> I get jj_
>
> How do I get the $VERSION to work with the underscores like the dashes
Hi all,
in a script if I have:
VERSION="3.2.0"
I can do:
echo jj-$VERSION-jj
and get jj-3.2.0-jj
however if I do:
echo jj_$VERSION_jj
I get jj_
How do I get the $VERSION to work with the underscores like the dashes do.
Thanks,
Jerry
___
CentOS mail
On Thu, Jun 4, 2009 at 10:27 AM, Stephen Harris wrote:
> On Thu, Jun 04, 2009 at 10:11:37AM -0400, Jacques B. wrote:
>
>> head -n 188 your_script | tail -n 3
>
>> That will output lines 186-188 so that you have some context (in case
>
> sed -n 186,188p your_script
>
> :-)
>
> --
>
> rgds
> Stephen
On Thu, Jun 04, 2009 at 10:11:37AM -0400, Jacques B. wrote:
> head -n 188 your_script | tail -n 3
> That will output lines 186-188 so that you have some context (in case
sed -n 186,188p your_script
:-)
--
rgds
Stephen
___
CentOS mailing list
CentOS
On Thu, Jun 4, 2009 at 9:47 AM, Jerry Geis wrote:
> I have this line:
> ALSA=`aplay --version`
>
> in a script. when I execute the script I get the message
> line 187: --version: command not found
>
> when I do "aplay --version" on the command line it works just fine.
>
> What is happe
> I have this line:
> ALSA=`aplay --version`
>
> in a script. when I execute the script I get the message
> line 187: --version: command not found
What's in line 187?
Do you really want to use backticks ` or should it be more like
ALSA='aplay --version' (apostrophes)? If you want
Jerry Geis wrote:
> I have this line:
> ALSA=`aplay --version`
>
> in a script. when I execute the script I get the message
> line 187: --version: command not found
>
$ echo $(aplay --version)
aplay: version 1.0.18 by Jaroslav Kysela
t
I have this line:
ALSA=`aplay --version`
in a script. when I execute the script I get the message
line 187: --version: command not found
when I do "aplay --version" on the command line it works just fine.
What is happening here, --version is a valid command line option?
Thanks,
j
Jerry Geis wrote:
> Hi all,
>
> I am trying to create a script that takes an entire file,
> drops the first 19 characters from each line and creates a new file.
[..]
> test.txt is below
> 10-Oct-08 08:14 am 10
If this is the format of your data you could use awk to do the same
thing
cat filename
Filipe Brandenburger wrote:
Hi,
On Wed, Oct 15, 2008 at 10:48, Jerry Geis <[EMAIL PROTECTED]> wrote:
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
newline=`echo $LINE | cut -f 19-`
What you want is "cut -c
Hi,
On Wed, Oct 15, 2008 at 10:48, Jerry Geis <[EMAIL PROTECTED]> wrote:
> I am trying to create a script that takes an entire file,
> drops the first 19 characters from each line and creates a new file.
> newline=`echo $LINE | cut -f 19-`
What you want is "cut -c 19-" (-c as in characters)
On Wed, October 15, 2008 10:48 am, Jerry Geis wrote:
> Hi all,
>
> I am trying to create a script that takes an entire file,
> drops the first 19 characters from each line and creates a new file.
>
> I am missing something easy but I am not seeing it.
>
> Jerry
>
> ---
> I tried the script below bu
Hello Jerry-
Simply change the line:
newline=`echo $LINE | cut -f 19-`
to this:
newline=`echo $LINE | cut -c 19-`
You want to cut based on 'c'haracters, not 'f'ields. :-)
Tim Nelson
Systems/Network Support
Rockbochs Inc.
(218)727-4332 x105
- "Jerry Geis" <[EMAIL PROTEC
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
I am missing something easy but I am not seeing it.
Jerry
---
I tried the script below but did not work.
rm output.txt
cat test.txt | \
while read LINE
do
ne
Hi all,
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
I am missing something easy but I am not seeing it.
Jerry
---
I tried the script below but did not work.
rm output.txt
cat test.txt | \
while read LINE
do
24 matches
Mail list logo
