OK, I feel like I've done this before, but maybe not. Can anyone explain to
me how to do this and get my desired result.
cfloop query=querya
cfloop query=queryb
#querya.val#: #queryb.val#
/cfloop
/cfloop
What I want is, if querya had 2 rows and queryb had 3 rows, to get
Reverse your loops:
cfloop query=queryb
cfloop query=querya
#querya.val#, #queryb.val#
/cfloop
/cfloop
John
At 04:24 PM 10/3/01 -0400, you wrote:
OK, I feel like I've done this before, but maybe not. Can anyone explain to
me how to do this and get my desired
: Wednesday, October 03, 2001 5:36 PM
To: CF-Talk
Subject: Re: Nested Loops (query)
Reverse your loops:
cfloop query=queryb
cfloop query=querya
#querya.val#, #queryb.val#
/cfloop
/cfloop
John
At 04:24 PM 10/3/01 -0400, you wrote:
OK, I feel
This solution won't work. What is happening is that you are referring
to only the first row in your inner cfloop, in regards to querya, which
is why you are only getting the output of the first value in the first
row. Reversing the process will simply reverse the output you are
getting, not
On 10/3/01, Sean Daniels penned:
cfloop query=querya
cfloop query=queryb
#querya.val#: #queryb.val#
/cfloop
/cfloop
This will work:
cfloop query=querya
cfset querya_value = val
cfloop query=queryb
CFOUTPUT#querya_value#: #val#br/CFOUTPUT
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