Re: Nested Loops (query)

2001-10-03 Thread Bud
On 10/3/01, Sean Daniels penned: > > > > > #querya.val#: #queryb.val# > > > > This will work: #querya_value#: #val# -- Bud Schneehagen - Tropical Web Creations _/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/ ColdFusion Solutions / eCommerce Develop

RE: Nested Loops (query)

2001-10-03 Thread John Paitel
>This solution won't work. What is happening is that you are referring >to only the first row in your inner cfloop, in regards to querya, which >is why you are only getting the output of the first value in the first >row. Reversing the process will simply reverse the output you are >getting, not

RE: Nested Loops (query)

2001-10-03 Thread Andrew Tyrone
cfoutput loop is on, as that is implicit as well. Basically the inner row count and variable names take precedence over any outer loops with the same variable names. -Andy > -Original Message- > From: John Paitel [mailto:[EMAIL PROTECTED]] > Sent: Wednesday, October 03,

Re: Nested Loops (query)

2001-10-03 Thread John Paitel
Reverse your loops: #querya.val#, #queryb.val# John At 04:24 PM 10/3/01 -0400, you wrote: >OK, I feel like I've done this before, but maybe not. Can anyone explain to >me how to do this and get my desired result. > > > > > > #querya.val#: #qu

Nested Loops (query)

2001-10-03 Thread Sean Daniels
OK, I feel like I've done this before, but maybe not. Can anyone explain to me how to do this and get my desired result. #querya.val#: #queryb.val# What I want is, if querya had 2 rows and queryb had 3 rows, to get 6 rows of output like this: querya.row1: queryb.row1