Couldn't you replace all instances of Chr(13) (I think that's right...) with
a null?
--
Jamie Keane
Programmer
SolutionMasters, Inc.
9111 Monroe Rd., Suite 100
Charlotte, NC 28270
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704.849.7771 x 228 Voice
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-Original Message-
From: Bryan
What is the best way to strip CRs and LFs from a string?
cfset crlf = chr(13)chr(10)
cfset stripped = replacelist(myString,crlf,"")
Should do the trick.
- Sean
~~
Structure your ColdFusion code with Fusebox. Get the official book at
Use the Replace function. The best way is to do a replace for CR and then
one for LF. as they could be in any order, generally though it should be
CRLF.
The character codes for LF is 10 and CR is 13 (I think!).
I this should work
cfset x=#Replace(x,chr(13),"","ALL")#
cfset
--
At the macro level, it may appear that I am doing
nothing. But at the cellular level I am really
quite busy.
-Original Message-
From: Jamie Keane [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, January 09, 2001 9:36 AM
To: CF-Talk
Subject: Re: Stripping CRs and LFs
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