8:47 AM
To: CF-Talk
Subject: RE: Transact SQL question has me stumped
Dennis... Learn something new everyday. I guess I did not know there was
bit operator in CF :)
-Original Message-
From: Dennis Powers [mailto:[EMAIL PROTECTED]
Sent: Tuesday, February 05, 2008 1:11 PM
To: CF-Talk
Subjec
Dennis... Learn something new everyday. I guess I did not know there was
bit operator in CF :)
-Original Message-
From: Dennis Powers [mailto:[EMAIL PROTECTED]
Sent: Tuesday, February 05, 2008 1:11 PM
To: CF-Talk
Subject: RE: Transact SQL question has me stumped
Mark,
I knew I would
Jeff,
>> Ah, you changed the question :) You originally said AND, now it is OR!
I knew I was phrasing it incorrectly mixing Boolean and linguistic
"and"
>> WHERE myColumn & myMask > 0
This is much too easy and I can't believe I overlooked so simple a basic
Boolean solution. That sound you hear
Ah, you changed the question :) You originally said AND, now it is OR!
It doesn't change the problem much.
Step 1: Create your mask
Step 2: Zero out the bits we don't care about with
Step 3: If we are left with anything, we have records that contain a flag.
WHERE myColumn & myMask > 0
enjoy!
doh! That should be 2^0 + 2^7 (silly me)
> myMask = 2^1 + 2 ^8
~|
Adobe® ColdFusion® 8 software 8 is the most important and dramatic release to
date
Get the Free Trial
http://ad.doubleclick.net/clk;160198600;22374440;w
Archive
Jeff,
>> myMask = 2^1 + 2 ^8
>> SELECT mycolumns
>> FROM mytable
>> WHERE BigIntColumn & #myMask# = #myMask#
This was exactly what I was doing - irrespective of the CAST to change data
types - but it will only select records that have bit 1 AND Bit 8. What I
need to do is to select records th
Original Message-
From: Dennis Powers [mailto:[EMAIL PROTECTED]
Sent: Tuesday, February 05, 2008 2:02 PM
To: CF-Talk
Subject: RE: Transact SQL question has me stumped
>> You need a bitwise operator. Bit and is & in MS SQL
>> SELECT mycolumns
>> FROM mytable
>
I'm not Guru, but this should do it.
First you create a mask by turning on the bits you need.
myMask = 2^1 + 2 ^8
Then, bitwise AND (&) with your column. The result needs to be equal to your
mask to have all the specific bits turned on. NOTE: This assumes you don't care
about the value in the
>> You need a bitwise operator. Bit and is & in MS SQL
>> SELECT mycolumns
>> FROM mytable
>> WHERE bit_column & 128 = 128
This was essentially what I was doing but it does not work properly for
matching multiple bits in the "bit_column", Example: matching a row that
has Bit 1 and Bit 8 (129)
Original Message-
From: Dennis Powers [mailto:[EMAIL PROTECTED]
Sent: Tuesday, February 05, 2008 1:11 PM
To: CF-Talk
Subject: RE: Transact SQL question has me stumped
Mark,
I knew I would most likely not explain it properly. The existing database
has a column that contains values that ar
Mark,
I knew I would most likely not explain it properly. The existing database
has a column that contains values that are typed as a BigInt. I have a
filter that gets constructed from Bit values for example: the filter = 129
which was constructed from bit 1 binary + bit 8 Binary 1 + 128.
What
work :)
-Mark
-Original Message-
From: Dennis Powers [mailto:[EMAIL PROTECTED]
Sent: Tuesday, February 05, 2008 12:01 PM
To: CF-Talk
Subject: Transact SQL question has me stumped
I am hoping an SQL guru can assist me with what I am sure is a stupid little
oversight or misunderstanding on my p
I am hoping an SQL guru can assist me with what I am sure is a stupid little
oversight or misunderstanding on my part.
I hope I can explain this. I need to do a bit evaluation against data in the
database where the data is stored in a BigInit column. Within my code I
construct a bit filter and nee
13 matches
Mail list logo
