Hi all,
I'm trying to understand how continuations work, and tried out the first
example described at
"https://en.wikibooks.org/wiki/Scheme_Programming/Continuations"; with
Chicken (5.1):
---
(define continuations '())
(define (push arg)
(set! c
> Could someone please explain what's going on? Why would Chicken append
> the new list to the old value of 'numbers', which as I understand should
> be empty at the moment of the stored continuation?
You are re-entering the execution of "map" by calling the stored
continuation, which was at tha
Am 19.10.2019 14:18 schrieb felix.winkelm...@bevuta.com:
The exact behaviour of re-
entering a continuation captured during execution of "map" is, I think,
dependent on implementation details (there may be a note about this in
the
SRFI-1 document or R7RS, I can't remember right now).
Many tha
Ricardo Gabriel Herdt writes:
> Am 19.10.2019 14:18 schrieb felix.winkelm...@bevuta.com:
>> The exact behaviour of re-
>> entering a continuation captured during execution of "map" is, I think,
>> dependent on implementation details (there may be a note about this in
>> the
>> SRFI-1 document o
Am 19.10.2019 15:46 schrieb megane:
There's special compiler syntax for map; search for 'map-loop in the
sources. You can also see what your code expands to by giving -debug 2
flag to csc.
Thanks megane,
with -debug 2 I see that map uses some local variables that are changed
with set! in the
> I found this in R5RS/R7RS/SRFI-1: "The dynamic order in which proc is
> applied to the elements of the lists is unspecified". Indeed redefining
> map in all implementations as
>
> (define (map f l)
>(cond ((null? l) '())
> (else (cons (f (car l))
> (map f (cdr l))
>
> make all be
Am 19.10.2019 18:57 schrieb felix.winkelm...@bevuta.com:
But what I forgot, and which may be the confusing part is that
after the mapping is complete, "numbers" (in your example) will be
assigned once again - the continuation includes everything following
the invocation of "map". Only the REPL
