On Sat, Jul 12, 2014 at 2:20 PM, Evan Hanson wrote:
> Hi Michele,
>
> csc(1) will read source from standard input given the filename "-".
>
> $ csc -o quick_test -
> (print 1)
> ^D
> $ ./quick_test
> 1
Oh, very well. Sorry for not reading the documentation beforehand.
> Wheth
Hi Michele,
csc(1) will read source from standard input given the filename "-".
$ csc -o quick_test -
(print 1)
^D
$ ./quick_test
1
Whether csc(1) should default to standard input when no filename is
given is a matter for debate, but that's how it's done as things are.
Regar
Hi all,
I think it would be useful if csc were able to work directly from the
standard input (e.g. in case of no source files). For example:
csc -o quick_test
[paste code]
Ctrl-D
./quick_test
or
cat f.scm | preprocessor | csc
./a.out
On most Unixes you can obtain the result with /dev/stdin, bu
