On Sat, Jan 05, 2008 at 03:48:00PM +0100, Hans Bulfone wrote:
this is exactly how i hoped it to be, but the question is if this
is actually allowed or if it just works accidentally.
r5rs doesn't seem to specify this case and '( . x) is not allowed.
FWIW, SRFI-1 does specify this case, and
hi,
On Sat, Jan 05, 2008 at 03:10:51PM -0600, Zbigniew wrote:
Hans,
If I understand correctly, you're asking whether this is valid:
`(,@'() . x) ;= x
yes.
i should have written my question more concisely :)
According to Quasiquotation in Lisp (Alan Bawden), ... the most
thanks for the
hi,
in a macro i'm constructing a lambda-list in the following way:
`(,@rqd-args . ,rest-arg)
there are 3 cases:
1. (let ((rqd-args '(a b c)) (rest-arg 'r)) `(,@rqd-args . ,rest-arg))
== (a b c . r)
2. (let ((rqd-args '(a b c)) (rest-arg '())) `(,@rqd-args . ,rest-arg))
== (a b c)
so
Hans Bulfone scripsit:
this is exactly how i hoped it to be, but the question is if this
is actually allowed or if it just works accidentally.
It is indeed valid to have a lambda-list that is just an identifier,
in which case that identifier is bound to a list of all the arguments.
See the
Hans,
If I understand correctly, you're asking whether this is valid:
`(,@'() . x) ;= x
According to Quasiquotation in Lisp (Alan Bawden), ... the most
useful expansion of `(,@anything) is (append anything). So in order
to give nested splicing a useful semantics, the code constructed by
read
