I sketched your network and it made me wonder if the path you think is
"shortest" really is shortest.
To get to the C routers in Area 2, the Area 1 A routers have four possible
paths:
1. A1---T3---B1---B2---T3---C2
2. A1---T3---B1---T1---C1
3. A2---T1---B2---T3---C2
4. A2---T1---B2---B1---T1--
OSPF (Open Shortest Path First) calculates the shortest path to area 0
first, then the shortest path to the next area boundary via intra-area
routes. The best illustration of this was in the Networkers 2000 CCIE Power
Session presentation
http://www.ieng.com/networkers/nw00/pres/3304/3304_c1_sec2
Sorry, I meant to say that I would have expected B2's cost to be 3 not 2.
Curtis Call wrote:
> Are you sure that the B1 Network Summary LSA had a lower cost then the B2
> Summary LSA? According to how I understood your topology, B1 should
advertise
> a cost of 65 to reach network C and B2 shoul
Are you sure that the B1 Network Summary LSA had a lower cost then the B2
Summary LSA? According to how I understood your topology, B1 should
advertise
a cost of 65 to reach network C and B2 should advertise a cost of 2. So they
should both use the T1 link to B2 to exit the area. The reason for
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