Everybody's showing you the intelligent way, so I thought I'd try showing
you my "Subnetting for dummies" method - Works for me- If you can follow the
explanation, the calculation is childs play (Please excuse all incorrect
network terms used for explanation (broken octets, chunks etc)):
"Say I h
""Wojtek Zlobicki"" wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > And if you are allowing IP subnet-zero, then you have subnets=(2^18)-1
or
> > 262143 subnets.
>
> Does ip subnet zero also not allow an all ones subnet , making the total
> 262144 (can't remember in which IOS th
> And if you are allowing IP subnet-zero, then you have subnets=(2^18)-1 or
> 262143 subnets.
Does ip subnet zero also not allow an all ones subnet , making the total
262144 (can't remember in which IOS this started becoming possible)
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And if you are allowing IP subnet-zero, then you have subnets=(2^18)-1 or
262143 subnets.
As far as network and broadcast addresses are concerned:
For your example of 10.100.0.0/26, the network address is 10.100.0.0, and
the broadcast address is 10.100.0.63
Don't even get me started on the new
so = /18 = 2^18 - 2
Number of subnet is 262142.
Hunt Lee wrote:
> It would be great if someone can give me a hand on this: I know how to
> calculate the number of subents and number of hosts per subent, but I'm
> very confused about the Network address and the Broadcast address:
>
> Say I hav
It would be great if someone can give me a hand on this: I know how to
calculate the number of subents and number of hosts per subent, but I'm
very confused about the Network address and the Broadcast address:
Say I have a network: 100.10.0.0 255.255.255.192:
1) To work out the subnet:
100.1
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