Is there a function in clojure.core or clojure.contrib so that:
(and (mystery-fn '(a b c d) '(a b))
(not (mystery-fn '(a b c d) '(a b d
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On Fri, Jul 17, 2009 at 1:32 PM, samppirbysam...@gmail.com wrote:
Is there a function in clojure.core or clojure.contrib so that:
(and (mystery-fn '(a b c d) '(a b))
(not (mystery-fn '(a b c d) '(a b d
how about something like:
(defn mystery-fn [l1 l2] (every? identity (map = l1
Awesome, thanks for the quick answer. I think that it'd be a useful
thing to add to seq-utils or something. :)
On Jul 17, 1:41 pm, Mark Engelberg mark.engelb...@gmail.com wrote:
On Fri, Jul 17, 2009 at 1:32 PM, samppirbysam...@gmail.com wrote:
Is there a function in clojure.core or
On Fri, Jul 17, 2009 at 4:41 PM, Mark Engelberg mark.engelb...@gmail.comwrote:
On Fri, Jul 17, 2009 at 1:32 PM, samppirbysam...@gmail.com wrote:
Is there a function in clojure.core or clojure.contrib so that:
(and (mystery-fn '(a b c d) '(a b))
(not (mystery-fn '(a b c d) '(a b
