>From INT.h.in:
828 #if !defined(@KWIML@_INT_NO_INTPTR_T)
829 @KWIML@_INT__VERIFY_TYPE(@KWIML@_INT_intptr_t, sizeof(void*));
830 #endif
831 #if !defined(@KWIML@_INT_NO_UINTPTR_T)
832 @KWIML@_INT__VERIFY_TYPE(@KWIML@_INT_uintptr_t, sizeof(void*));
833 #endif
Now this
Probably a moot question at this point... I posed the same question to some of
the language/compiler experts at HPE and got the following explanation:
Looking quickly, I suspect that he is not using the /pointer=long qualifier at
compile time.
The default pointer size is 32-bit (4 bytes), but