Given a C++ class wrapped with Boost.Python:
class CPPClass {
void test();
}
BOOST_PYTHON_MODULE(testmodule)
{
class_<CPPClass>("CPPClass")
.def("test", &CPPClass::test)
;
}
I've created a python subclass and redefined the metaclass:
class Meta(CPPClass.__class__):
def __new__(cls, name, bases, attrs):
return super(Meta, cls).__new__(cls, name, bases, attrs)
class PyClass(CPPClass):
__metaclass__ = Meta
Any attempt to call methods of PyClass, or to pass it as an argument to a C++
function results in an ArgumentError. It appears that ob_type is being tested
for equivalence to the Boost.Python.class type.
I am currently working around this by using a plain function as the metaclass,
but it's not ideal as each base class must set the metaclass explicitly.
I browsed through object/class.cpp, and I think using PyType_IsSubtype() in
place of == &class_metatype_object should be sufficient to allow me to derive
metaclasses from Boost.Python.class.
Does anyone have any advice, comments or objections before I proceed?
James
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