Hi all,
I'm trying to expose a base-class with pure virtual functions, and a
derived class. Following the example here:
http://www.boost.org/doc/libs/1_42_0/libs/python/doc/tutorial/doc/html/python/exposing.html#python.class_virtual_functions
both in my real code, and in a minimal test-case, I get
On 03/14/2010 04:28 PM, Anders Wallin wrote:
Hi all,
I'm trying to expose a base-class with pure virtual functions, and a
derived class. Following the example here:
http://www.boost.org/doc/libs/1_42_0/libs/python/doc/tutorial/doc/html/python/exposing.html#python.class_virtual_functions
both in
Thanks, inserting a few "public" keywords here and there makes this compile:
class Base {
public:
virtual int f(int x) = 0;
};
class Derived : public Base {
public:
int f(int x) {return 2*x;}
};
class BaseWrap : public Base, public boost::python::wrapper
{
public:
On 03/14/2010 05:37 PM, Anders Wallin wrote:
not sure if this is worth mentioning in the documentation, or is it
very obvious to everyone except newbies like myself... :)
Knowing that access to base classes and members defaults to 'public' for
structs and 'private' for classes is basic C++
