Hi,
I have written a sample DLL in C++. It has a class and functions for add,
sub, mul and div.
I wrote a wrapper class in the same file as BOOST_PYTHON_MODULE(hello).
Now when I compiled this DLL, I get Test.DLL.
Now from Python, I wrote a script to load this Test.DLL.
How can I access add, s
On Wed, Jun 6, 2012 at 5:09 AM, Nagaraju wrote:
> I wrote a wrapper class in the same file as BOOST_PYTHON_MODULE(hello).
>
> Now when I compiled this DLL, I get Test.DLL.
Hmm, the module thinks its name is "hello", but it's in Test.DLL?
Maybe it should be hello.pyd?
The .pyd is to designate it
Hi Nat,
Thank you very much for your reply. I am sorry if I did not explain
something clearly.
The output file I am generating is as Test.DLL only. I am not generating it
as .pyd.
This DLL has a class called MyClass. In it, I have add, sub, mul n div.
I am doing as below after implementing the
On Wed, Jun 6, 2012 at 6:57 AM, Nagaraju wrote:
> Thank you very much for your reply. I am sorry if I did not explain
> something clearly.
>
> I am doing as below after implementing the MyClass in the same file:
>
> BOOST_PYTHON_MODULE(hello){
> ...
> }
>
> I am using CDLL from ctypes to load thi
Hi Nat,
Thank you very much for the reply.
I tried making the target as ".pyd" and I am able to import it in Python
script.
Thanks again.
Regards,
Raju.
On Wed, Jun 6, 2012 at 6:57 PM, Nat Linden wrote:
> On Wed, Jun 6, 2012 at 6:57 AM, Nagaraju
> wrote:
>
> > Thank you very much for your rep
